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Dima020 [189]
3 years ago
14

The law of what energy states that energy cannot be created or destroyed

Physics
2 answers:
nlexa [21]3 years ago
7 0

The answer to your question is "The Law of Conservation of Energy." It states that matter or energy cannot be created or destroyed, it can only be changed in form.

Dmitriy789 [7]3 years ago
4 0

Answer:

the answer is conversation

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In this graph, what is the displacement of the particle in the last teo seconds?
White raven [17]

Answer: B

Explanation:

Displacement is a vector quantity. it is the distance covered in a specific direction.

Whereas, Velocity = displacement/time

Make displacement the subject of formula

Displacement = velocity × time

From the graph, velocity is constant which is equal to 1 m/s

Displacement in the last two seconds will be velocity multiply by 2. Since time = 2s. Therefore,

Displacement = 1 × 2 = 2 m

So, the particle displacement in the last two seconds will be 2 metres

6 0
3 years ago
Carla is babysitting her 2-year-old nephew for the first time. While her back is turned just for a moment, he touches the pan sh
defon

Answer:

Screaming is an emotional response triggered by the brain which receives information about the pain later as compared to pulling away of finger which is a reflex action facilitated by the spinal cord that has a quicker-time to response.

Explanation:

Reflex action happens when part of our body comes to contact with an object which can cause harm and you tend to quickly withdraw that part of the body.Reflex action happens quicker before the brain gets the time to process information about the harm.

When the baby touched the hot pan, at point of contact, skin receptors send nerve impulses to the spinal cord. Interneurons in the spinal cord relay a response to motor neurons to stimulate muscle contraction making the baby to pull his finger away.This happens so fast before the brain receives the message later to trigger emotional response(screaming).

4 0
3 years ago
A force of 8 N accelerates by 4 m/s^2. What would be the amount of force needed to give a final acceleration of 5.3 m/s^2
Elis [28]

Answer:

10.6 N

Explanation:

F = ma

8 = m * 4

m = 2 kg

F = 2 * 5.3

F = 10.6 N

4 0
2 years ago
Why do we experience a high tide twice a day?
Veseljchak [2.6K]

Coastal areas experience two low tides and two high tides every lunar day, or 24 hours and 50 minutes. The two tidal bulges caused by inertia and gravity will rotate around the Earth as the moons position changes. These bulges represent high tides while the flat sides indicate low tides.

Over the course of 1 day, the position of the moon does not change very much compared to the rotation of the earth. As the earth rotates below the moon, one point on the earth will go through all levels of tide as the day passes by. Strongly attracted, middling, weakly attracted, and then middleagain. From our perspective it looks like "high, low, high, low." Or equivalently you can think about how the points below the moon and opposite the moon will be high tide, and as the earth rotates, those areas will change.

7 0
3 years ago
A moving curling stone, A, collides head on with stationary stone, B. Stone B has a larger mass than stone A. If friction is neg
Kitty [74]

Answer:

The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.

Explanation:

Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively

and the mass of big rock be 'M'

Initial momentum of the system equals

p_i=mv+0=mv

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'

Thus the final momentum of the system is

p_f=mv'+MV'

Equating initial and the final momenta we get

mv=mv'+MV'\\\\m(v-v')=MV'.....i

Now since the surface is frictionless thus the energy is also conserved thus

E_i=\frac{1}{2}mv^2

Similarly the final energy becomes

E_f=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\

Equating initial and final energies we get

\frac{1}{2}mv^2=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\\\\mv^2=mv'^2+MV'^2\\\\m(v^2-v'^2)=MV'^2\\\\m(v-v')(v+v')=MV'^2......(ii)

Solving i and ii we get

v+v'=V'

Using this in equation i we get

v'=\frac{v(m-M)}{(M-m)}=-v

Thus putting v = -v' in equation i  we get V' = 0

This implies Smaller stone rebounds while as larger stone remains stationary.

4 0
3 years ago
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