F(2) = 3(2)^2 + 2(2) + 4
= 3(4) + 4 + 4
= 12 + 8
f(2) = 20
f(a+h) = 3(a+h)^2 + 2(a+h) + 4
= 3(a^2 + 2ah + h^2) + 2a + 2h + 4
f(a+h) = 3a^2 + 6ah + 3h^2 + 2a + 2h + 4
3/4, x, and y that is the answer
Answer:
35/132.
Step-by-step explanation:
There are a total of 12 balls. So:
Prob(First is green) = 5/12.
After the first selection there are 11 balls left.
Prob(The second is red) = 7/11.
The required probability = 5/12 * 7/11
= 35/132.
Note: the probabilities are multiplied because the 2 events are independent.
Answer:
D) The very last one
Step-by-step explanation:
n + 6 < 4
n < -2
< means it's an open circle and goes in the LEFT direction
