2 years ago

Explain why the value of the sin ratio for an acute angle of a right triangle must always be positive value less than 1

Mathematics

1 answer:

NARA [144]2 years ago

7 0

Because the ratio always have to be greater than 1

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Sedbober [7]

F(-4) = 6, f(0) = -6, f(1) = -4

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3 years ago

If Judy has 4 blouses and 5 skirts, how many different outfits of a blouse and skirt can she wear?

Aloiza [94]

Answer:

Step-by-step explanation:

i think but not fur shure

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2 years ago

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Can anyone help with this? I will mark you as brainliest!

Pavel [41]

Answer:

1.25x10^2

Step-by-step explanation:

5x5^2

5x5x5=125

125=1.25x10^2

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3 years ago

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Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

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3 years ago

How many solutions does this equation have?

Greeley [361]

Answer:

No solution

Explanation:

-4+19-7f = -15-7

cancel terms on both sides ( add 7f on both sides)

Calculate the sum

-4+19= -15

-4+19=15

15 = -15

The statement 15 = -15 is false so there is no solution :)

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2 years ago