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Korolek [52]
3 years ago
9

Please help! Which of the following values in the set below will make the equation 2x + 1 = 3 true? (Only input the number.) {0,

1, 2, 3, 4} (5 points)
Mathematics
2 answers:
pochemuha3 years ago
7 0

Answer:

1

Step-by-step explanation:

(2x1) +1 = 3

x=1

mihalych1998 [28]3 years ago
4 0

Answer: The value of x = 1.

Step-by-step explanation: I only inputted the answer as you said. Hope this helps!

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Cedric purchased a new refrigerator and stove at Home Depot for $3,729 on a deferred payment plan with no down
lesya [120]

Answer:

correct option is d. $242.81

Step-by-step explanation:

given data  

APR = 25.5% = \frac{25.5}{12}     = 2.125  

paid = $3,729

solution

we get here finance charge on the 1st month by multiplying 3,729 and now adding it to existing balance

so we get finance charge for the second and third months similarly as

APR ÷ 100 = \frac{2.125 }{100}  = 0.02125

so 1st  

= $3,729 × 0.02125  

= 79.25  

and  

$3,729  + $79.25 = $3808.24  

so for next  

= $3808.24 × 0.02125  

= 80.93

and  

$3808.24  + $80.93 = $3889.17  

so for next  

= $3889.17  × 0.02125  

= 82.64  

and  

$3889.17 + $ 82.64  = $3971.81

so  

finance charge =  3971.81 - 3729  

finance charge = 242.81  

so correct option is d. $242.81

8 0
3 years ago
A small business earns a profit of $4,500 in
olchik [2.2K]

Answer:

$2750/month

Step-by-step explanation:

7 0
3 years ago
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Select all the statements that are true for the graph shown
SVEN [57.7K]

Answer:

there is nothing to prove

Step-by-step explanation:

6 0
2 years ago
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How many distinct pairs of perfect squares differ by 35? (the pair $a, b$ is the same as the pair $b, a$.)?
Phantasy [73]
35 has 4 divisors, hence two factor pairs: 1*35 and 5*7. Each corresponds to a set of perfect squares that differ by 35

One pair is ((35±1)/2)^2 = {17^2, 18^2} = {289, 324}
The other is ((7±5)/2)^2 = {1^2, 6^2} = {1, 36}
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="f(x) = \sqrt{x} " alt="f(x) =
Georgia [21]

Answer:    \dfrac{1}{2\sqrt x}

<u>Step-by-step explanation:</u>

\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}

f(x) = \sqrt x\\

f(x+h) = \sqrt{x+h}

\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}

                   =\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)

                   =\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}

                   =\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}

                   =\dfrac{1}{\sqrt{x+h}+\sqrt x}

                  =\dfrac{1}{\sqrt{x+0}+\sqrt x}

                  =\dfrac{1}{2\sqrt x}

4 0
3 years ago
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