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Korolek [52]
3 years ago
9

Please help! Which of the following values in the set below will make the equation 2x + 1 = 3 true? (Only input the number.) {0,

1, 2, 3, 4} (5 points)
Mathematics
2 answers:
pochemuha3 years ago
7 0

Answer:

1

Step-by-step explanation:

(2x1) +1 = 3

x=1

mihalych1998 [28]3 years ago
4 0

Answer: The value of x = 1.

Step-by-step explanation: I only inputted the answer as you said. Hope this helps!

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It would be about 4/10 of a gallon
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nekit [7.7K]

Answer:

I got -60

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6 0
2 years ago
What is 8 is increased to 22
SOVA2 [1]
<span><span>1.       </span>What is 8 increased to 22.
I believe you want me to show you what is the interest increased from 8 to 22
Let’s start the solution process:
=> 8 is the original number and supposed to be the 100% value
=> 22 is the increased number
subtract 22 by 8 to know how much is added.
=> 22 – 8 = 14
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Thus, the added increased is around 175% of the original money</span>



3 0
3 years ago
Someone help please
Alla [95]

Answer:  Choice A

\tan(\alpha)*\cot^2(\alpha)\\\\

============================================================

Explanation:

Recall that \tan(x) = \frac{\sin(x)}{\cos(x)} and \cot(x) = \frac{\cos(x)}{\sin(x)}. The connection between tangent and cotangent is simply involving the reciprocal

From this, we can say,

\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\

In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.

All of this shows why \tan(\alpha)*\cot^2(\alpha)\\\\ is identical to \frac{\cos(\alpha)}{\sin(\alpha)}\\\\

Therefore, \tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\ is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.

You can visually confirm that \tan(\alpha)*\cot^2(\alpha)\\\\ is the same as \frac{\cos(\alpha)}{\sin(\alpha)}\\\\ by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.

6 0
2 years ago
Someone pls HELP RN IM IN A HURRY
Serga [27]

BC AB AC

Step-by-step explanation:

the longer the side is visually detected ok

7 0
2 years ago
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