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3 years ago

Tina’s cat weighs 2.6 kilograms her dog weighs 4 times as much as her cat . How much does her cat and dog weigh in all

Mathematics

1 answer:

denis-greek [22]3 years ago

7 0

Answer in kilograms: 10.4 kilograms
Answer in grams: 10,400

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Which relationships describe the angle pair x° and 157º?

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supplementary angles.

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3 years ago

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3 years ago

A 3-gallon bottle of fabric softener costs $28.92. What is the price per quart?

bixtya [17]

Answer:

$2.41

Step-by-step explanation:

There are 4 quarts in a gallon. If there are 3 gallons that means there is 12 quarts (3x4=12) You then take $28.92 and divide it by 12, which will give you 2.40833333 and on and on, you round that to $2.41. I hope that helps!

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3 years ago

An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of mov- ing violatio

olga2289 [7]

Answer:

a) $E(Y) = \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60$

b) $E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1$

And then the expected value would be:

$E(100Y^2) = 100*1.1= 110$

Step-by-step explanation:

We assume the following distribution given:

Y 0 1 2 3

P(Y) 0.60 0.25 0.10 0.05

Part a

We can find the expected value with this formula:

$E(Y) = \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60$

Part b

If we want to find the expected value of $100 Y^2$ we need to find the expected value of Y^2 and we have:

$E(Y^2) = \sum_{i=1}^n Y^2_i P(Y_i)$

And replacing we got:

$E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1$

And then the expected value would be:

$E(100Y^2) = 100*1.1= 110$

4 0

3 years ago