A small first-aid kit is dropped by a rock climber who is descending steadily at 1.3 m/s. After 2.5 s, what is the velocity of t
1 answer:
You might be interested in
To solve this task we have to make a proportion, but firstly we have to set up all the main points : so, the distance is s=r(B), that has its <span>r=radius,B=angle in rad
velocity v=ds/dt= w(r)
Do not forget about </span> w = angular speed in rad/s and
Now we can go to proportion
SOLVING FOR A :
or something about <span>10 mph --- SOLVING FOR B.
</span>I'm sure it helps!
Do not forget about </span> w = angular speed in rad/s and
Now we can go to proportion
SOLVING FOR A :
</span>I'm sure it helps!
The current intensity is defined as the amount of charge flowing through a certain point of a wire divided by the time interval:
where Q is the charge and
is the time. Re-arranging the formula, we have
for the compressor in our problem, the intensity of current is I=66.1 A, while the time is
, so the amount of charge that crosses a certain point of the circuit during this time is
where Q is the charge and
for the compressor in our problem, the intensity of current is I=66.1 A, while the time is