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zubka84 [21]
3 years ago
12

Unpolarized light is incident on a series of polarizing disks. We have three polarizers A, B and C have transmission axes that m

ake angles of 30, 90 and 180 degrees, respectively, measured CW from the vertical y-axis. You want to maximize the relative transmission and can place them in any order. What is the maximum possible relative transmission (is. Final/I0) passing through a series of all three polarizers
Physics
1 answer:
ikadub [295]3 years ago
3 0

Answer:

Explanation:

Formula for intensity of light after transmission for unpolarised light is

I₀ / 2 , We shall take up 180 degree disk first .

For second transmission , the formula is

I = I₀ Cos²θ , θ is angle between axis of polarizer and axis of vibration.

If we take up 30 degree polariser

I = I₀ / 2  Cos²( 180 - 30 )

= .375 I₀

For third transmission

I_ final = .375 I₀  x cos( 90 - 30 )

= .1875  I₀

Final/I₀ = .1875  

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bagirrra123 [75]

Answer:

0.650

Explanation:

Move the decimal point three times to the left.

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The weight of a body kept at a distance of 6400 km from the centre of the
Vlad [161]

Answer:

2.5N

Explanation:

since force is inversely proportional to square of the distance apart. that means the ratio of distance apart. so u have 12800×12800÷(6400××6400)=4/1

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Outside our solar system the closest star to earth is Proxima century life from the start takes 2200000 minutes to reach earth.
s2008m [1.1K]

Answer:

2200000 = 2.2E6 min for light from Proxima to reach earth

8.3 min from light sun to reach earth

2.2E6/8.3 = 2.56E5   times for light from Proxima

Proxima is about 256,000 times farther away than the sun

Since the sun is about 93,000,000 = 9.3E7 miles from earth

Proxima is then 9.3E7 * 2.56E5 = 2.4E13 miles away

Note - the speed of light is

3.00E8 m/s * 60 s/min / 1000 m/km = 1.8E7 km/min as given

5 0
2 years ago
A bus travel with an average velocity of 60km/h. How long does it take to cover a distance of 500km​
Mnenie [13.5K]

Around 8 hours and 20 minutes

Explanation:

I divided 500 by 60 and got 8.3333333333 and i round it up to 8.20, so it is 8 hours and 20 minutes.

8 0
3 years ago
Calculate the force of gravity between a comet with a mass of 500kg and a small asteroid with a mass of 20kg that is separated b
givi [52]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The equivalent gravitational force is ~

  • F  \approx1.48\times 10 {}^{ - 7}  \: \: N

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

We know that ~

\huge\boxed{\mathrm{F = \dfrac{ Gm_1m_2}{ r²}}}

where,

  • F = gravitational force

  • m_1 = mass of 1st object = 500 kg

  • m_2 = mass of 2nd object = 20kg

  • G = gravitational constant = 6.674 × {10}^ {-11}

  • r = distance between the objects = 2.12 m

Let's calculate the force ~

  • F = \dfrac{6.674   \times 10 {}^{ - 11} \times 500 \times 20}{(2.12) {}^{2} }

  • F = \dfrac{6.674  \times 10 {}^{ - 11} \times 10 {}^{4} }{4.4944}

  • F =  \dfrac{6.674}{4.4944}  \times 10 {}^{ - 7}

  • F =1.484 \times 10 {}^{ - 7}  \: \: newtons
7 0
2 years ago
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