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zubka84 [21]
3 years ago
12

Unpolarized light is incident on a series of polarizing disks. We have three polarizers A, B and C have transmission axes that m

ake angles of 30, 90 and 180 degrees, respectively, measured CW from the vertical y-axis. You want to maximize the relative transmission and can place them in any order. What is the maximum possible relative transmission (is. Final/I0) passing through a series of all three polarizers
Physics
1 answer:
ikadub [295]3 years ago
3 0

Answer:

Explanation:

Formula for intensity of light after transmission for unpolarised light is

I₀ / 2 , We shall take up 180 degree disk first .

For second transmission , the formula is

I = I₀ Cos²θ , θ is angle between axis of polarizer and axis of vibration.

If we take up 30 degree polariser

I = I₀ / 2  Cos²( 180 - 30 )

= .375 I₀

For third transmission

I_ final = .375 I₀  x cos( 90 - 30 )

= .1875  I₀

Final/I₀ = .1875  

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Name the two scales that are used to measure earth intensity
nikklg [1K]

Answer:

Although several scales have been developed over the years, the two commonly used today in the United States are the moment magnitude scale, which measures magnitude (M), or size, and the Modified Mercalli scale, which measures intensity.

3 0
4 years ago
Who exerts more pressure? a) A girl of 50 kg, wearing heels with an area of 1 cm2. b) An elephant of 4000 kg with foot area of 2
Mrrafil [7]

Answer:

The girl exerts more pressure.

Explanation:

Pressure can be defined as the force exerted normally or perpendicularly per unit area.

i.e P = F/A

<u>Girls</u>

Area of the heel = 1cm² = 10^(-4) m²

Force = mg = 50 × 10 = 500N

Pressure =

\frac{500}{10 ^{ - 4} }

= 5 \times  {10}^{6}

<u>Elephant</u>

<u>Area</u><u> </u><u>=</u><u> </u><u>2</u><u>5</u><u>0</u><u>cm</u><u>²</u><u> </u><u>=</u><u> </u><u>2</u><u>.</u><u>5</u><u> </u><u>x</u><u> </u><u>1</u><u>0</u><u>^</u><u>(</u><u>-</u><u>2</u><u>)</u><u>b</u><u> </u><u>m</u><u>²</u>

<u>Force</u><u> </u><u>=</u><u> </u><u>mg</u><u> </u><u>=</u><u> </u><u>4</u><u>0</u><u>0</u><u>0</u><u>0</u><u>N</u>

<u>Pressure</u><u> </u><u>=</u><u> </u>

<u>\frac{40000}{2.5 \times  {10}^{ - 2} }</u>

<u>= 1.6 \times  {10}^{6}</u>

5 0
3 years ago
A 55.6-kg skateboarder starts out with a speed of 2.44 m/s. He does 80.4 J of work on himself by pushing with his feet against t
Vikentia [17]

(a) -1620.8 J

The initial kinetic energy of the  skateboarder is:

K_i = \frac{1}{2}mu^2 = \frac{1}{2}(55.6 kg)(2.44 m/s)^2=165.5 J

where m is the skateboarder's mass and u his initial speed;

While the final kinetic energy is

K_f = \frac{1}{2}mv^2 = \frac{1}{2}(55.6 kg)(7.24 m/s)^2=1457.2 J

where v is his final speed.

So the change in kinetic energy is

\Delta K=K_f - K_i = 1457.2 J -165.6 J = 1291.6 J

According to the work-energy theorem, the change in mechanical energy (kinetic+potential) of the skateboarder is equal to the work done on it:

\Delta K + \Delta E_p = W + W_f

where

W = 80.4 J is the work done by the skateboarder on himself

W_f = -244 J is the work done by friction

\Delta E_p = E_p_f - E_p_i is the change in gravitational potential energy

Solving for \Delta E_p,

\Delta E_p = W+W_f - \Delta K=80.4 J - 244 J - 1457.2 J = -1620.8 J

(b) 2.97 m

The change in potential energy of the skateboarder can be written as

\Delta E_p = mg \Delta h

where

m = 55.6 kg is the mass

g = 9.8 m/s^2 is the acceleration of gravity

\Delta h is the change in vertical height of the skateboarder

Solving for \Delta h,

\Delta h = \frac{\Delta E_p}{mg}=\frac{-1620.8 J}{(55.6 kg)(9.8 m/s^2)}=-2.97 m

Where the negative sign means the skateboarder has moved downwards. Since we are interested only in the absolute value, the answer is

h = 2.97 m

7 0
3 years ago
What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 29.0 km/h and the co
bazaltina [42]

Answer:

Explanation:

Let the radius of track required be r.

Centripetal force will be provided by frictional force which will be equal to

m v²/ r

Frictional force = mg x μ

So

m v² /r = mg μ

r = v² / μ g =

  v = 29 km /h = 8.05 m /s

r =( 8.05 x 8.05 ) /( .32 x 9.8 ) = 20.66 m

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3 years ago
River deltas are _____.
Leto [7]
<h3><u>Answer;</u></h3>

formed by erosion

River deltas <u>are formed by erosion</u>.

<h3><u>Explanation;</u></h3>
  • <em><u>River delta refers to a landform that forms from deposition of sediment carried by a river as the flow leaves its mouth and enters slower-moving or stagnant water.</u></em>
  • In other words <em><u>river deltas are wetlands that form as rivers empty their water and sediment into another body of water, such as an ocean, lake, or another river</u></em>. It occurs when a River is entering a sea, an ocean, lake a reservoir or another river that is incapable of carrying the supplied sediment.
  • Therefore,<u> deltas are formed as a result of erosion by water</u> which involves the carrying of sediments down the rivers to the mouth of river where it accumulates.

7 0
3 years ago
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