WILL GIVE BRAINLIEST

Physics

1 answer:

SpyIntel [72]3 years ago

6 0

Answer:

The force exerted by the brakes is 14,400,000 N

Explanation:

Initial kinetic energy of truck = 72 MJ

Work done by the breaks, W = Force exerted by the brakes × Distance, D, the truck came to stop

The distance, D, in which the truck came to a stop is given as 5 meters

Given that the initial kinetic energy, KE of the truck that was reduced by the breaks = The work done by the brakes

We have;

W = ΔKE = Change in kinetic energy

ΔKE = Initial kinetic energy - Final Kinetic Energy

Initial kinetic energy, KE = 72 MJ

Final Kinetic Energy = 0 J (Truck stopped)

ΔKE = 72 - 0 = 72 MJ

Therefore we have;

Force exerted by the breaks = W/D = 72 MJ/5 = 14.4 MN. = 14,400,000 N.

You might be interested in

A 4.0-n puck is traveling at 3.0 m/s. it strikes an 8.0-n puck, which is stationary. the two pucks stick together. their common

Natalka [10]

<span>1.0 m/s Momentum = mass x velocity Total Momentum before any collision = total momentum afterwards 4.0 x 3.0= 12 :g x momentum before (x g because using weight) Afterwards, if the velocity of the two joined is v then we get: 'momentum x g'=12v so 12v=12 so v=1m/s</span>

3 0

3 years ago

A car is driving at 99 km/h, calculate the distance it travels in 70 minutes.

Lapatulllka [165]

Answer:

The distance the car travels is 115500 m in S.I units

Explanation:

Distance d = vt where v = speed of the car and t = time taken to travel

Now v = 99 km/h. We now convert it to S.I units. So

v = 99 km/h = 99 × 1000 m/(1 × 3600 s)

v = 99000 m/3600 s

v = 27.5 m/s