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Lera25 [3.4K]
3 years ago
9

Which of the following leads to a higher rate of effusion?

Chemistry
1 answer:
Basile [38]3 years ago
6 0

Answer:

b. Lower molar mass.

Explanation:

  • <em>Thomas Graham</em> found that, at a constant  temperature and pressure the rates of effusion  of various gases are inversely proportional to  the square root of their masses.

<em>∨ ∝ 1/√M.</em>

where, ∨ is the rate of diffusion of the gas.

M is the molar mass of the gas.

<em>As the gas has a lower molar mass, it will have a higher rate of effusion.</em>

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What kind of bonding is found in Fe2O3?​
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Answer:

Ionic

Explanation:

Any metal with a nonmetal is an ionic bond due to the transfer of electrons from one element to another.

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3 years ago
Write the charge and full ground-state electron configuration of the monatomic ion most likely to be formed by each:
Sladkaya [172]

Answer:

Part A:

Charge is P^{3-}

Configuration is 1s^2 2s^22p^63s^23p^6

Part B:

Charge is Mg^{2+}

Configuration is 1s^2 2s^22p^6

Part C:

Charge is Se^{2-}

Configuration is 1s^2 2s^22p^63s^23p^64s^23d^{10}4p^6

Explanation:

Monatomic ions:

These ions consist of only one atom. If they have more than one atom then they are poly atomic ions.

Examples of Mono Atomic ions: Na^+, Cl^-, Ca^2^+

Part A:

For P:

Phosphorous (P) has 15 electrons so it require 3 more electrons to stabilize itself.

Charge is P^{3-}

Full ground-state electron configuration of the mono atomic ion:

1s^2 2s^22p^63s^23p^6

Part B:

For Mg:

Magnesium (Mg) has 12 electrons so it requires 2 electrons to lose to achieve stable configuration.

Charge is Mg^{2+}

Full ground-state electron configuration of the mono atomic ion:

1s^2 2s^22p^6

Part C:

For Se:

Selenium (Se) has 34 electrons and requires two electrons to be stable.

Charge is Se^{2-}

Full ground-state electron configuration of the mono atomic ion:

1s^2 2s^22p^63s^23p^64s^23d^{10}4p^6

8 0
3 years ago
How do you find the volume of a liquid
mart [117]
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7 0
3 years ago
What is the volume of 40g of sugar given it’s listed density
lora16 [44]

Answer:

25.157 cm³

Explanation:

Data Given:

Mass of Sugar (m) = 40g

Density of sugar given in literature = 1.59 g/cm³

Volume of Sugar = ?

The formula will be used is

                              d = m/v ........................................... (1)

where

D is density

m is the mass

v is the volume

So

Rearrange the Equation (1)

                              d x v = m

                               v = m/ d         ................................................ (2)

put the given values in Equation  (2)

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Which substance can be broken down by a chemical change
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