Chemical reactions can be detected by changes in temperature
Answer:
![Excess=3.53g](https://tex.z-dn.net/?f=Excess%3D3.53g)
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
![2Mg(s)+O_2(g) \rightarrow 2MgO(s)](https://tex.z-dn.net/?f=2Mg%28s%29%2BO_2%28g%29%20%5Crightarrow%202MgO%28s%29)
Next, we identify the limiting reactant by computing the moles of magnesium oxide yielded by 3.86 g of magnesium and 155 mL of oxygen at the given conditions via their 2:1:2 mole ratios and the ideal gas equation:
![n_{MnO}^{by \ Mg}=3.86gMg*\frac{1molMg}{24.3gMg}*\frac{2molMgO}{2molMg} =0.159molMgO\\\\n_{MnO}^{by \ O_2}=\frac{1atm*0.155L}{0.082\frac{atm*L}{molO_2*K}*275K} *\frac{2mol MgO}{1molO_2} =0.0137molMgO](https://tex.z-dn.net/?f=n_%7BMnO%7D%5E%7Bby%20%5C%20Mg%7D%3D3.86gMg%2A%5Cfrac%7B1molMg%7D%7B24.3gMg%7D%2A%5Cfrac%7B2molMgO%7D%7B2molMg%7D%20%20%3D0.159molMgO%5C%5C%5C%5Cn_%7BMnO%7D%5E%7Bby%20%5C%20O_2%7D%3D%5Cfrac%7B1atm%2A0.155L%7D%7B0.082%5Cfrac%7Batm%2AL%7D%7BmolO_2%2AK%7D%2A275K%7D%20%2A%5Cfrac%7B2mol%20MgO%7D%7B1molO_2%7D%20%3D0.0137molMgO)
It means that the limiting reactant is the oxygen as it yields the smallest amount of magnesium oxide. Next, we compute the mass of magnesium consumed the oxygen only:
![m_{Mg}^{consumed}=0.0137molMgO*\frac{2molMg}{2molMgO} *\frac{24.3gMg}{1molMg} =0.334gMg](https://tex.z-dn.net/?f=m_%7BMg%7D%5E%7Bconsumed%7D%3D0.0137molMgO%2A%5Cfrac%7B2molMg%7D%7B2molMgO%7D%20%2A%5Cfrac%7B24.3gMg%7D%7B1molMg%7D%20%3D0.334gMg)
Thus, the mass in excess is:
![Excess=3.86g-0.334g\\\\Excess=3.53g](https://tex.z-dn.net/?f=Excess%3D3.86g-0.334g%5C%5C%5C%5CExcess%3D3.53g)
Regards!
Answer:
nucleus
Alpha particles are subatomic fragments consisting of two neutrons and two protons. Alpha radiation occurs when the nucleus of an atom becomes unstable (the ratio of neutrons to protons is too low) and alpha particles are emitted to restore balance.
Explanation:
Answer:
Option A.
Explanation:
To know which structure is correct, let us name both compound.
In naming the above organic compound, the following must be observed:
1. Locate the functional group. In this case it alkene since it has carbon to carbon double bond (C=C).
2. Locate the longest continuous carbon chain. In this case the compound is a cyclic compound with 6 carbon i.e cyclohexene.
3. Locate the substituents attached to the compound. In this case, bromine (bromo) and chlorine (chloro) are the substituents attached.
4. Locate the position of the substituents and name alphabetically counting from the double bond. In this case, bromo comes before chloro
5. Combine the above to get the name.
For option A, the name is:
4–bromo–5–chlorocyclohexene.
For option B, the name is:
3–bromo–4–chlorocyclohexene.
We can see that Option A gives the correct structure of the compound.