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Aleksandr [31]
3 years ago
9

Expand and simplify (x - 2)^2 these are the options 2 + 4 + 4 2 − 4 2 − 4 + 4 2 + 4

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
7 0

Answer:

x^2-4x+4

Step-by-step explanation:

(x - 2)^2

(x - 2)(x - 2)

x(x-2)-2(x-2)

x^2-2x-2x+4

x^2-4x+4

pochemuha3 years ago
3 0

Answer:

{x}^{2}  - 4x + 4 \\

Step-by-step explanation:

{(x - 2)}^{2}  \\ (x - 2)(x - 2) \\ x(x - 2) - 2(x - 2) \\  {x}^{2}  - 2x - 2x + 4 \\  {x}^{2}  - 4x + 4

hope this helps you

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Determine which function has the greatest rate of change as x approaches infinity.
Mekhanik [1.2K]

Answer: h(x) = 3*x^2 - 7*x + 8

Step-by-step explanation:

The rate of change of a function is equal to the derivate:

remember that a derivate of the form:

k(x) = a*x^n is k'(x) = n*a*x^(n-1)

Then we have:

f(x) = 2*x - 10

f'(x) = 1*2* = 2

g(x) = 16*x - 4

g'(x) = 1*16 = 16

h(x) = 3*x^2 - 7*x + 8

h'(x) = 2*3*x - 1*7 = 6*x - 7

So the only that increases as x increases is h(x), this means that the greates rate of change as x approaches inffinity is the rate of change of h(x)

3 0
3 years ago
Instructions:Select the correct answer from each drop-down menu. ∆ABC has vertices at A(11, 6), B(5, 6), and C(5, 17). ∆XYZ has
Akimi4 [234]

to compare the triangles, first we will determine the distances of each side

<span>Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
</span>Solving 

<span>∆ABC  A(11, 6), B(5, 6), and C(5, 17)</span>

<span>AB = 6 units   BC = 11 units AC = 12.53 units
</span><span>∆XYZ  X(-10, 5), Y(-12, -2), and Z(-4, 15)
</span><span>XY = 7.14 units   YZ = 18.79 units XZ = 11.66 units</span>

<span>∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).</span>

<span>MN = 6 units   NO = 11 units MO = 12.53 units
</span><span>∆JKL  J(17, -2), K(12, -2), and L(12, 7).
</span><span>JK = 5 units   KL = 9 units JL = 10.30 units
</span><span>∆PQR  P(12, 3), Q(12, -2), and R(3, -2)
</span><span>PQ = 5 units   QR = 9 units PR = 10.30 units</span> 
Therefore
<span>we have the <span>∆ABC   and the </span><span>∆MNO  </span><span> 
with all three sides equal</span> ---------> are congruent  
</span><span>we have the <span>∆JKL  </span>and the <span>∆PQR 
</span>with all three sides equal ---------> are congruent  </span>

 let's check

 Two plane figures are congruent if and only if one can be obtained from the other by a sequence of rigid motions (that is, by a sequence of reflections, translations, and/or rotations).

 1)     If ∆MNO   ---- by a sequence of reflections and translation --- It can be obtained ------->∆ABC 

<span> then </span>∆MNO<span> ≅</span> <span>∆ABC  </span> 

 a)      Reflexion (x axis)

The coordinate notation for the Reflexion is (x,y)---- >(x,-y)

<span>∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).</span>

<span>M(-9, -4)----------------->  M1(-9,4)</span>

N(-3, -4)------------------ > N1(-3,4)

O(-3,-15)----------------- > O1(-3,15)

 b)      Reflexion (y axis)

The coordinate notation for the Reflexion is (x,y)---- >(-x,y)

<span>∆M1N1O1  M1(-9, 4), N1(-3, 4), and O1(-3, 15).</span>

<span>M1(-9, -4)----------------->  M2(9,4)</span>

N1(-3, -4)------------------ > N2(3,4)

O1(-3,-15)----------------- > O2(3,15)

 c)   Translation

The coordinate notation for the Translation is (x,y)---- >(x+2,y+2)

<span>∆M2N2O2  M2(9,4), N2(3,4), and O2(3, 15).</span>

<span>M2(9, 4)----------------->  M3(11,6)=A</span>

N2(3,4)------------------ > N3(5,6)=B

O2(3,15)----------------- > O3(5,17)=C

<span>∆ABC  A(11, 6), B(5, 6), and C(5, 17)</span>

 ∆MNO  reflection------- >  ∆M1N1O1  reflection---- > ∆M2N2O2  translation -- --> ∆M3N3O3 

 The ∆M3N3O3=∆ABC 

<span>Therefore ∆MNO ≅ <span>∆ABC   - > </span>check list</span>

 2)     If ∆JKL  -- by a sequence of rotation and translation--- It can be obtained ----->∆PQR 

<span> then </span>∆JKL ≅ <span>∆PQR  </span> 

 d)     Rotation 90 degree anticlockwise

The coordinate notation for the Rotation is (x,y)---- >(-y, x)

<span>∆JKL  J(17, -2), K(12, -2), and L(12, 7).</span>

<span>J(17, -2)----------------->  J1(2,17)</span>

K(12, -2)------------------ > K1(2,12)

L(12,7)----------------- > L1(-7,12)

 e)      translation

The coordinate notation for the translation is (x,y)---- >(x+10,y-14)

<span>∆J1K1L1  J1(2, 17), K1(2, 12), and L1(-7, 12).</span>

<span>J1(2, 17)----------------->  J2(12,3)=P</span>

K1(2, 12)------------------ > K2(12,-2)=Q

L1(-7, 12)----------------- > L2(3,-2)=R

 ∆PQR  P(12, 3), Q(12, -2), and R(3, -2)

 ∆JKL  rotation------- >  ∆J1K1L1  translation -- --> ∆J2K2L2=∆PQR 

<span>Therefore ∆JKL ≅ <span>∆PQR   - > </span><span>check list</span></span>
6 0
3 years ago
C=27+10h where c= cost in dollars and h= number of hours rented ​
gavmur [86]

Answer:

that help

Step-by-step explanation:

10h+27+−27=c+−27

10h=c−27

10h10=c−2710

h=110c+−2710

Answer:

h=110c+−2710

3 0
3 years ago
The volume of an oblique pyramid with a square base is V units3 and the height is h units. Which expression represents the area
givi [52]

Answer:

Area of the base of the pyramid = V/h

Step-by-step explanation:

Mathematically, we know that the volume of the pyramid can be calculated by multiplying the area of the base by the height of the pyramid

Now using the variables in the question;

V = area of base * height of pyramid

Area of base = V/height of pyramid

Area of base = V/h

3 1
3 years ago
In a competative exam of 40 questions plus three months is awarded for a correct answer and minus one for every correct answer t
Alex Ar [27]

Answer:

76

Step-by-step explanation:

n a competitive exam of 40 questions, +3 is awarded for a correct answer and -1 for every wrong answer. Find the total score if a student had 11 wrong answers in his attempt of all questions.

Answers gotten wrong = 11

answers gotten right = 40 - 11 = 29

total score = (point for correct answer x number of correct answer) +  (point for wrong answer x number of wrong answer)

(+3 x 29) + (-1 x 11) = 76

6 0
3 years ago
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