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atroni [7]
3 years ago
13

I need the two most abundant gases in the atmosphere and their approximate proportions please and thank you :)

Chemistry
1 answer:
timofeeve [1]3 years ago
8 0
The most abundant gases in the atmosphere are:

N₂ ⇒ 78%
O₂ ⇒ 21%
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What is the Lewis Structure for silane?
julia-pushkina [17]
SIH4 Silicon tetrahyrdide
7 0
3 years ago
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Q05 the "atomic number" of an atom is determined by the number of ________ it has.
Alexxx [7]
The atomic number of an atom is determined by the number of protons it has..

It is also the whole number shown on the periodic table 
6 0
4 years ago
3- a) write the formula unit of calcium fluoride.
zvonat [6]

Answer:

a) CaF₂.

b) 7.81g of CaF₂ are present.

Explanation:

a) The calcium ion has as charge Ca²⁺ and fluoride ion is F⁻, that means formula unit is:

CaF₂

b) 1 molecule of CaF₂ contains 2 anions, F⁻. Thus, the moles of CaF₂ is:

1.2x10²³ anions * (1 moleculeCaF₂ / 2 anions) = 6x10²² molecules of CaF₂

6.022x10²³ molecules = 1mol:

6x10²² molecules of CaF₂ * (1mol / 6.022x10²³molecules) = 0.10 moles CaF₂.

1 mole of CaF₂ has a mass of 78.07g:

0.10 moles CaF₂ * (78.07g / mol) =

7.81g of CaF₂ are present

5 0
3 years ago
What is the value of the equilibrium constant for this redox reaction?
aivan3 [116]
Correct  answer: Option D, <span>K = 5.04 × 10^52
</span>
Reason:
We know that, 
Ecell = \frac{0.0592}{n}log(K),
where n = number of electrons = 2 (in present case)
K = equilibrium constant.

Also, Ecell = <span>+1.56 v

Therefore, 1.56 = </span>\frac{0.0592}{2}log(K)
Therefore, log (K) = 52.703
Therefore,  K = 5.04 X 10^52


8 0
3 years ago
Read 2 more answers
Li + HNO3 &gt; LiNO3 + H2 how do I balance it? Show work pls
azamat

Answer: The balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

Explanation:

The given reaction equation is as follows.

Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}

Number of atoms present on reactant side are as follows.

  • Li = 1
  • H = 1
  • NO_{3} = 1

Number of atoms present on product side are as follows.

  • Li = 1
  • H = 2
  • NO_{3} = 1

To balance this equation, multiply Li by 2 and HNO_{3} by 2 on reactant side. Also, multiply LiNO_{3} by 2 on product side.

Hence, the equation can be rewritten as follows.

2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}

Now, number of atoms present on reactant side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

Number of atoms present on product side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

3 0
3 years ago
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