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Katarina [22]
3 years ago
13

A bacteria has a doubling period of 5 days. If there are 2350 bacteria present now, how many will there be in 22 days?

Mathematics
1 answer:
topjm [15]3 years ago
6 0
First abswer is 51700
Sexond answer is 10340
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Points F(3, 3), K(6, 5), J(8, 2) and L(5, 0) lie in a coordinate plane. Which lines are perpendicular?
Romashka-Z-Leto [24]
To determine if a line is perpendicular to another, you must first determine the slope...
m = y1-y2/x1-x2
m of FK = 3-5/3-6 = -2/-3 = 2/3
m of FJ = 3-2/3-8 = 1/-5
m of FL = 3-0/3-5 = 3/-2
m of KJ = 5-2/6-8 = 3/-2
m of KL = 5-0/6-5 = 5
m of JL = 2-0/ 8-5 = 2/3

In order for two lines to be perpendicular, their slopes must be opposite reciprocals...
FK is perpendicular to FL
FK is perpendicular to KJ
JL is perpendicular to FL
JL is perpendicular to KJ
FJ is perpendicular to KL
8 0
3 years ago
PLEASE ANSWER
liraira [26]
Answer: the heart works to pump through the body systems
5 0
3 years ago
I dont know the answer!! I give brainlist...​
iragen [17]

Answer:

A.   (f + g)(1) = - 9

B.    (f - g)(0) = -7

C.    (fg)(3) = 0

Step-by-step explanation:

A.    (f + g)(1) = f(1) + g(1)               f(1) = 1^2 - 9 = 1 - 9 = - 8       g(1) = 1 - 2 = - 1

                    = -8 -1 = -9

B.     (f - g)(0) = f(0) - g(0)             f(0) = 0^2 - 9 = 0 - 9 =  -9      g(0) = 0 - 2 = -2

                      =  -9 + 2 = -7

C.      (fg)(3) = f(3)(g(3)                   f(3) = 3^2 - 9 = 9 - 9 = 0    g(3) = 3 - 2 = 1

                    = 0(1) = 0

4 0
3 years ago
the student council has 36 membersthe ratio of girls to boys is 5 to 4 how many student council members are girls?
kap26 [50]
Ratio of girls : boys = 5 : 4

<u>Find total parts:</u>
Total parts = 5 + 4 = 9

<u>Find 1 part:</u>
9 parts = 36
1 part = 36 ÷ 9 = 4

<u>Find 5 parts (Girls):</u>
Girls = 5 parts = 4 x 5 = 20

Answer: There are 20 girls.
8 0
3 years ago
PLZZ HELP!! WILL MARK BRAINLIEST PLZZ!!!
grandymaker [24]

Answer:

see below

Step-by-step explanation:  7  1  16   33

  y  = x²   translated t the point (3, 2)         y = 0 when x = 0

  y =  (x - 3)²    moves the function three units to the right     y = 0 when x = -3

  y  = (x-3)² + 2  moves the function up 2 units      y = 2 when x = -3

  y = (x-3)² + 2

  y = x² - 6x + 9 + 2

  y = x² - 6x +11

graph the equations x²,  (x-3)² + 2,  and x² - 6x + 11   to verify (I did)

7 0
3 years ago
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