Answer:
a) The current density ,J = 2.05×10^-5
b) The drift velocity Vd= 1.51×10^-15
Explanation:
The equation for the current density and drift velocity is given by:
J = i/A = (ne)×Vd
Where i= current
A = Are
Vd = drift velocity
e = charge ,q= 1.602 ×10^-19C
n = volume
Given: i = 5.8×10^-10A
Raduis,r = 3mm= 3.0×10^-3m
n = 8.49×10^28m^3
a) Current density, J =( 5.8×10^-10)/[3.142(3.0×10^-3)^2]
J = (5.8×10^-10) /(2.83×10^-5)
J = 2.05 ×10^-5
b) Drift velocity, Vd = J/ (ne)
Vd = (2.05×10^-5)/ (8.49×10^28)(1.602×10^-19)
Vd = (2.05×10^-5)/(1.36 ×10^10)
Vd = 1.51× 10^-5
Answer:
Upthrust = 20 N
Explanation:
The question says that "A body weighs 100N in air and 80N when submerged in water. Calculate the upthrust acting on the body
?"
Upthrust is defined as the force when a body is submerged in liquid, then liquid applies a force on it.
ATQ,
Weight of body in air is 100 N
Weight of body in water is 80 N
Upthrust is equal to the weight of body in air minus weight of body in water.
Upthrust = 100 N - 80 N
Upthrust = 20 N
So, 20 N of upthrust is acting on the body.
Answer:
Displacement = 70 m towards east
Explanation:
Displacement is the shortest distance between the two points.
Let us say that he starts at the point O and travels in a path ABC.
If we join the initial and final point of the path travelled by him, it will give the displacement of the man.
Distance from O to A = 40 m
Distance from A to B = 70 m
Distance from B to C = 40 m
Distance from O to A = Distance from B to C
We want the displacement which is distance between the points O and C
In rectangle opposite sides are equal. Hence Distance from O to C = Distance from A to B
Displacement = Distance from A to B
Hope it helps,
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Answer:
It means that if force is constant, as mass is increased, acceleration decreases
Explanation:
Answer:
the answers are 1 2 and 5!
