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nikklg [1K]
3 years ago
13

3. In a physics lab, 0.500-kg cart (Cart A) moving rightward with a speed of 100 m/s collides with a 1.50-kg cart (Cart B) movin

g leftward with a speed of 20 m/s. The two carts stick together and move as a single object after the collision. Determine the post-collision speed of the two carts.
Physics
1 answer:
Alex787 [66]3 years ago
6 0

Answer:

The speed of the two carts after the collision is 10 m/s.

Explanation:

Hi there!

The momentum of the system Cart A - Cart B is conserved because there is no external force acting on the system at the instant of the collision. Then, the momentum of the system before the collision will be equal to the momentum of the system after the collision. The momentum of the system is calculated as the sum of momenta of cart A and cart B:

initial momentum = mA · vA1 + mB · vB1

final momentum = (mA + mB) · vAB2

Where:

mA = mass of cart A = 0.500 kg

vA1 = velocity of cart A before the collision = 100 m/s

mB = mass of cart B = 1.50 kg.

vB1 = velocity of cart B before the collision = - 20 m/s

vAB2 = velocity of the carts that move as a single object = unknown.

(notice that we have considered leftward as negative direction)

Since the momentum of system remains constant:

initial momentum = final momentum

mA · vA1 + mB · vB1 = (mA + mB) · vAB2

Solving for vAB2:

(mA · vA1 + mB · vB1) / (mA + mB) = vAB2

(0.500 kg · 100 m/s - 1.50 kg · 20 m/s) / (0.500 kg + 1.50 kg) = vAB2

vAB2 = 10 m/s

The speed of the two carts after the collision is 10 m/s.

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Over time Pangaea broke apart to form other continents.
Gelneren [198K]

Answer:

North America, Europe, and most of Asia.

<u><em>I hope this helped at all.</em></u>

5 0
3 years ago
Someone please help me with finding the resistance of these circuits! I've been asking for an hour now. I will give brainliest i
vivado [14]

Answer:

1. 59 Ω

2. 3 Ω

3. 0.625 kΩ

Explanation:

1. The total resistance in a series circuit is equal to the sum of the resistance.

R_T=R_1+R_2+R_3...\\R_T=20+19+20\\R_T=59

Therefore, the total resistance in the first circuit is 59 Ω.

2. The total resistance in a parallel circuit is equal to the sum of the reciprocals of the resistance.

\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} ...\\\frac{1}{R_T} = \frac{1}{6.0} +\frac{1}{12} +\frac{1}{36}+\frac{1}{18} \\\frac{1}{R_T} = \frac{1}{3} \\R_T=3

Therefore, the total resistance in the second circuit is 3 Ω.

3. This is another parallel circuit, so we use the same equation from above:

\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} ...\\\frac{1}{R_T} = \frac{1}{10} +\frac{1}{2} +\frac{1}{1} ...\\\frac{1}{R_T} =1.6\\R_T=\frac{1}{1.6}

Therefore, the total resistance in the third circuit is \frac{1}{1.6} kΩ, or 0.625 kΩ.

I hope this helps!

8 0
3 years ago
Farah claps his 600times in 60seconds. what is the friquency and periodb​
rosijanka [135]

Answer:

\huge\boxed{\sf Frequency = 10\ Hz}

\huge\boxed{\sf Time\ Period = 0.1\ secs}

Explanation:

<u>Given:</u>

No. of times = 600 times

Time = 60 seconds

<u>Required:</u>

Frequency = f = ?

Time Period = T = ?

<u>Solution:</u>

<h2>Frequency = No. of Times / Time</h2>

Frequency = 600 / 60

<u>Frequency = 10 Hz</u>

<h2>Time Period = 1 / Frequency</h2>

Time Period = 1 / 10

<u>Time Period = 0.1 secs</u>

5 0
3 years ago
the temperature of a body fell from 100°c to 50°c in 10 minutes. the surrounding temperature was 20°c. what is the temperature a
Anna007 [38]

Answer:

The temperature is 10 c

4 0
3 years ago
A car traveling at 23 m/s starts to decelerate steadily. It comes to a complete stop in 5 seconds. What is its acceleration?
kykrilka [37]
We could determine the acceleration using this formula
\boxed{a= \dfrac{v_{1}-v_{0}}{t} }

Given from the question v₀ = 23 m/s, v₁ = 0 (the car stops), t = 5 s
plug in the numbers
a= \dfrac{v_{1}-v_{0}}{t}
a= \dfrac{0-23}{5}
a= \dfrac{-23}{5}
a = -4.6
The acceleration is -4.6 m/s²
8 0
3 years ago
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