Answer:
0.0443 m/s
Explanation:
= Mass of honeybee = 0.15 g
= Mass of popsicle stick = 4.75 g
= Velocity of honeybee
= Velocity of stick = 0.14 cm/s
In this system the linear momentum is conserved
The velocity of the bee is 4.43 cm/s or 0.0443 m/s
Answer:
τ (bc. max) =25.37 MPa
Explanation:
From the question, T = 1.3Kn.m;
(G = 77.2 GPa) and from the image of this solid shaft system i attached;
d(ab) = 50mm; d(bc) = 38mm; L(ab) =0.2m and L(bc) = 0.25m
So ΣT = 0 → Ta + Tc = 1.3Kn.m
So the system is statically indeterminate.
Let's check at the equation that makes it compatible ;
ψ = 0 and ψ(c/b) + ψ(b/a) + ψ(a) = 0
[{T(bc)} / {J(bc)G}] + [{T(ab)} / {J(ab)G}] + 0 =
ΣT = 0 and T(bc) = T(c)
ΣT = 0 and T(ab) = T(c) - 1.3 Kn.m
Now,
[(T(c) x 250mm)/{(π/2)(19^4)}] + [{((T(c) - 1300000 Nmm) x 200mm}/{(π/2)(25^4)}] = 0
So, T(c) = 273374 Nmm = 273.374Nm
T(a) = 1300Nm - 273.374Nm = 1026. 63Nm
From the beginning we saw that;
T(bc) = T(c) = 273.374Nm
Now let's find the maximum shear stress in shaft BC;
τ (bc. max) = {τ (bc) x r(bc)} / J(bc)
τ (bc. max) = (273374Nmm x 19mm)/ {(π/2)(19^4)} = 5194106 / 204707
= 25.37 MPa
(a) 10.00V
(b) 0.5V
<h2>Explanation:</h2>(a) The power(P) supplied by a resistor of resistance (R) when a voltage(V) is passed across is given by;
P = V² / R ------------------(i)
From the question;
P = 5.00W
R = 20.00Ω
Substitute these values into equation (i) as follows;
5.00 = V² / 20.00
V² = 5.00 x 20.00
V² = 100.00
V =
Solve for V;
V = 10.00V
Therefore, the maximum voltage that can be applied without harming the resistor is 10.00V
(b) By Ohm's law the current (I) flowing through a resistor of resistance (R) when a voltage (V) is applied is given by;
V = I x R
=> I = V / R ----------------(ii)
Substitute the values of V and R into equation (ii) as follows;
I = 10.00 / 20.00
I = 0.5A
Therefore, the current through the resistor is 0.5A