Answer:
Volume of container = 0.0012 m³ or 1.2 L or 1200 ml
Explanation:
Volume of butane = 5.0 ml
density = 0.60 g/ml
Room temperature (T) = 293.15 K
Normal pressure (P) = 1 atm = 101,325 pa
Ideal gas constant (R) = 8.3145 J/mole.K)
volume of container V = ?
Solution
To find out the volume of container we use ideal gas equation
PV = nRT
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
First we find out number of moles
<em>As Mass = density × volume</em>
mass of butane = 0.60 g/ml ×5.0 ml
mass of butane = 3 g
now find out number of moles (n)
n = mass / molar mass
n = 3 g / 58.12 g/mol
n = 0.05 mol
Now put all values in ideal gas equation
<em>PV = nRt</em>
<em>V = nRT/P</em>
V = (0.05 mol × 8.3145 J/mol.K × 293.15 K) ÷ 101,325 pa
V = 121.87 ÷ 101,325 pa
V = 0.0012 m³ OR 1.2 L OR 1200 ml
Answer:
Formation of Gas, Color Change, and Absorption of heat is the Answer.
Explanation:
I just took the test.
It depends on which manner the formulae is being asked but the answer is: KNO3
Explanation:
it increases to stretch it farther
Answer:
Solution given:
e) The heating of sodium carbonate to produces sodium oxide and carbon dioxide
Solution given:
<u>Balanced</u><u> </u><u>chemical</u><u> </u><u>equation</u><u>:</u>

<u>when sodium carbonate is heated it decomposed and form sodium oxide and carbon dioxide</u>
<u>f</u>) chromium (III) hydroxide plus sulfuric acid
<u>Balanced chemical equation:</u>

<u>When chromium (III) hydroxide react with sulfuric acid double displacement takes place and forms produce chromium(III) sulfate and water.</u>
g) aluminum metal plus chlorine gas

<u>When aluminum metal is added to chlorine gas</u><u> </u><u>Combination reaction takes place and forms aluminum chloride.</u>