Answer:
5L
Explanation:
Please see the step-by-step solution in the picture attached below.
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Answer:
c) There are sharp emission lines demonstrating discrete energy levels.
Explanation:
When an element emits energy in the form of radiation, it produces a spectrum of colors on a photographic plate. This spectrum can either be continuous or discrete. In continuous spectrum the spectrum continues without any discrimination between two regions. This represents the continuous emission of radiation, and thus the continuous emission of energy without any break.
On the other hand, the line spectrum consists of discrete and sharp lines, which shows the emission of radiation in a certain amount in a certain time, with a break between emission. Hence, the line spectra supports the quantization of energy.
The correct option is:
<u>c) There are sharp emission lines demonstrating discrete energy levels.</u>
There are two equations of Gibb's free energy, ΔG°:
ΔG° = ΔH° - TΔS°
ΔG° = -RTlnK
Let's use the first equation. Since ΔS° is negligible, it is equal to 0. Therefore, ΔG° = ΔH° = 7.11 kJ/mol. We use this value to the second equation.
7.11 kJ/mol = -(8.314 J/mol·K)*(1 kJ/1000 J)*(25 + 273 K)*(lnK)
lnK = -2.8697
K = 0.05671
Therefore, the equilibrium constant is equal to 0.05671.
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