In a chemical reaction, _____________________ causes the reaction to stop by running out.

How does the electron configuration of elements within the same group compare? (A.) They all have their valence electrons in the

BaLLatris [955]

Answer:

( B) They all have their valence electrons in the same type of subshell.

Explanation:

With each period, a new shell is added to the atom.

Further, the groups are classified based on the type of subshell the last electron enters and number of valence electrons.

For all elements of same group, the last electron enters the same type of subshell.

Say, for group 1, last electron enters s orbital and they have 1 valence elctron.

for group 17, last electron enters p orbital and they have 7 valence electrons.

(A) and (D) are wrong because, energy level of the valence electrons is determined by the principle quantum number n and l and not by the type of subshell(only l) they enter.

(C) if the valence electron enters p orbital, then the elements will be placed in the p- block.

3 0

3 years ago

Nuclear power produces more toxic mercury than coal-burning power plants do.<br><br> True Or False?

andre [41]

True because it has more power than coal burning

3 0

3 years ago

Read 2 more answers

A gas has a volume of 0.50 L, a pressure of 0.5 atm, and a temperature of 40°C. What will be the new temperature if the gas is e

klio [65]

Answer:

4.90

Explanation:

10- 5.0

3 0

3 years ago

If a compound has a composition of 82% nitrogen and 18% hydrogen, what is the empirical formula for this compound

Damm [24]

Answer: The empirical formula for the given compound is $NH_3$

Explanation : Given,

Percentage of H = 18 %

Percentage of N = 82 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of H = 18 g

Mass of N = 82 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{18g}{1g/mole}=18moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{82g}{14g/mole}=5.8moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 5.8 moles.

For Hydrogen = $\frac{18}{5.8}=3.10\approx 3$

For Nitrogen = $\frac{5.8}{5.8}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of H : N = 3 : 1

Hence, the empirical formula for the given compound is $NH_3$

3 0

3 years ago

Calculate the concentration (M) of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to

Luda [366]

The concentration of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to a volume of 100 mL would be 0.1548 M.

<h3>Dilution</h3>

According to the dilution principle, the number of moles of solutes in a solution before and after dilution must be the same. This is expressed as the following equation:

$m_1v_1 = m_2v_2$

Where $m_1$ is the molarity before dilution, $v_1$ is the volume before dilution, $m_2$ is the molarity after dilution, and $v_2$ is the volume after dilution.