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Afina-wow [57]
3 years ago
9

How many atoms are bonded to the central atom in a fluorine (F2) molecule?

Chemistry
1 answer:
mylen [45]3 years ago
3 0

Answer:

Only one atom are bonded to the central atom in the F_{2}.

Explanation:

Fluorine most electronegative element.

The atomic number of fluorine is 9.

Electronic configuration - 1s^{2}2s^{2}2p^{4}

Hence, it required only one electron to get noble gas[Ne] electronic configuration.

In the F_{2} molecule two fluorine atoms are bonded by single covalent bond to get stability.

Each atom share one electron and form a bond.

The structure of F_{2} molecule is as follows.

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Answer: a) HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)

b) HCN : acid CN^- :conjugate base.

And, H_2O : base H_3O^+: conjugate acid.

c) HCN(aq.)+NaOH(aq)\rightleftharoons NaCN(aq.)+H_2O(l)

d) NaCN(aq)\rightarrow Na^+(aq.)+CN^-(aq)

e) NaCN(aq)+HCl(aq)\rightarrow NaCl(aq.)+HCN(aq)

Explanation:

a) Weak acid is defined as the acid which does not completely dissociates when dissolved in water. They have high pH. These releases H^+ ions in their aqueous states.

The equation for the dissociation of HCN acid is given by:

HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)

b) According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

HCN is loosing a proton, thus it is considered as an acid and after losing a proton, it forms CN^- which is a conjugate base.

And, H_2O is gaining a proton, thus it is considered as a base and after gaining a proton, it forms H_3O^+ which is a conjugate acid.

c) Neutralization reaction is a reaction in which an acid reacts with base to produce salt and water.

HCN(aq.)+NaOH(aq)\rightarrow NaCN(aq.)+H_2O(l)

d) The chemical equation for dissociation of NaCN in water.

NaCN(aq)\rightarrow Na^+(aq.)+CN^-(aq)

e) The chemical equation for the reaction of NaCN and HCI

NaCN(aq)+HCl(aq)\rightarrow NaCl(aq.)+HCN(aq)

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The third statement violates LCM because it means matter is created during a reaction, which is not true.

The last statement violates LCM because it means matter is lost during a reaction, which is not true.

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Solve to me this question
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