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3 years ago

Predict how many times you will roll a number less than 3 if you roll a standard number

Mathematics

1 answer:

Korvikt [17]3 years ago

4 0

Answer:

about 117 times

Step-by-step explanation:

No. of possible outcomes of a cube: 6

2 out the 6 possible outcomes are less than 3,

and therefore, No. of favorable outcome: 2

P(less than 3)= No. of favorable outcome / No. of possible outcomes

=2/6 => 1/3

if you roll a standard number cube 350 times then,

Prediction= number of rolls x (P(less than 3))

=350 x 1/3

≈117 times.

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The factors of x cube -10x square -53x-42

Verdich [7]

Answer:

$x^3 - 10 x^2 -53x -42 = ( x + 1)(x + 3) (x - 14)$

Step-by-step explanation:

$x^3 - 10x^2 -53x - 42$

The factors of 42 : ±1 , ±2 , ±3 , ±6, ±7, ±14, ±21 , ±42

Using trial and error method we will find the first root of the polynomial.

1 : ( 1 )³ - 10 ( 1 )² - 53 ( 1 ) - 42

1 - 10 - 53 - 42 ≠ 0

Therefore 1 is not a root

-1 : ( -1 )³ - 10 (- 1 )² - 53 (- 1 ) - 42

- 1 - 10 + 53 - 42

53 - 53 = 0

Therefore - 1 is a root of the polynomial.

Therefore ( x + 1) is a factor.

Now by long division or by using synthetic division we can find other factors.

Synthetic Division :

-1 | 1 -10 -53 - 42

| 0 - 1 11 42

|______________________

1 - 11 - 42 0

Therefore ,

$x^3 - 10 x^2 -53x -42 = ( x + 1)(x^2 - 11x +42)$ ------ ( 1 )

Next further factorize x² - 11x - 42

x² - 11x - 42

= x² - 14x + 3x - 42

=x(x - 14) + 3 (x - 14)

=(x + 3 )(x - 14)

Therefore ,

$x^3 - 10 x^2 -53x -42 = ( x + 1)(x + 3) (x - 14)$

4 0

3 years ago

HELP ASAP!!! Can Someone HELP ME WITH THIS? WILL GIVE BRAINLIEST AND 12 POINTS!

Alona [7]

Answer: LEAST-1/8 GREATEST-3/4

Step-by-step explanation:

5 0

3 years ago

Evaluate. 18.65 -52/11=

professor190 [17]

The answer is about 13.9927.

You would divide 52/11 and then subtract that decimal by 18.65.

18.65-4.7272=13.9927.

6 0

3 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. Use n to denote any arbitrary integer

lyudmila [28]

$f(\theta)=10\cos\theta+5\sin^2\theta$

then the derivative is

$f'(\theta)=-10\sin\theta+10\sin\theta\cos\theta$

Critical points occur where $f'(\theta)=0$ . This happens for

$-10\sin\theta+10\sin\theta\cos\theta=0$

$-10\sin\theta(1-\cos\theta)=0$

$\implies-10\sin\theta=0\text{ or }1-\cos\theta=0$

In the first case, we find

$-10\sin\theta=0\implies\sin\theta=0\implies\theta=n\pi$

In the second,

$1-\cos\theta=0\implies\cos\theta=1\implies\theta=2n\pi$

So all the critical points occur at multiples of $\pi$ , or $n\pi$ . (This includes all the even multiples of $\pi$ .)

3 0

3 years ago

A six-foot person walks from the base of a broadcasting tower directly toward the tip of the shadow cast by the tower. When the

mixas84 [53]

B. $\tan{\alpha}= \frac{h}{122+3}$

c.
$\tan{\alpha}=\frac{h}{122+3} = \frac{6}{3}
\\
\\ \frac{h}{125} = 2
\\
\\h=250$

4 0

3 years ago