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oksano4ka [1.4K]
4 years ago
9

g beats can be heard when Question 5 options: when sound waves interfere constructively when sound waves of same frequency inter

fere when sound waves of slightly different frequencies interfere when sound waves of different amplitudes interfere
Physics
1 answer:
Alika [10]4 years ago
3 0

Answer:

Explanation:

Beats are produced when two sound waves from two  different sources having slightly different frequencies  interfere . Due to both constructive and destructive interference , high and low intensity sound is heard at some regular interval . This is called rate of beat formation . Amplitudes of sound may be same or different . High intensity sound heard per unit time is called beat . It is equal to difference of frequencies of the sound waves interfering

each other .

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Drag the tiles to the correct boxes to complete the pairs. Match the symbols used in electric circuit diagrams to their function
Oksana_A [137]

<em>The question doesn't show symbols to match, but I'm giving you some common examples to help you out with your own assignment. </em>

Answer:

<em>List below</em>

Explanation:

<u>Electric Devices </u>

Electricity is usually converted into a variety of other forms of energy, like mechanical, chemical, nuclear, potential, thermal, among many others.  

The devices listed below convert electricity in the mentioned forms of energy

  • A speaker converts electric energy into sound energy
  • A light bulb glows when it receives current
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4 0
4 years ago
A car accidently rolls off acliff. As it leaves the cliff it has a horizontal of 13m/s, it hits they ground 60m from the shoreli
zimovet [89]

Answer:

jsudyve elected

Explanation:

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8 0
3 years ago
A wave has a frequency of 2 Hz. How many waves are produced in one minute?
Vlad1618 [11]

Answer:

see below

Explanation:

2 Hz, means 2 complete waves are produced in one second, so

2 waves ----- 1 second

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8 0
3 years ago
A 40 kg slab rests on a frictionless floor. A 10 kg block rests on top of the slab (Fig. 6-58). The coefficient of static fricti
vovikov84 [41]

Answer:

<u>\text { The "resulting action" on the slab is } 0.98 \mathrm{m} / \mathrm{s}^{2}</u>

Explanation:

Normal reaction from 40 kg slab on 10 kg block

M × g  = 10 × 9.8 = 98 N  

Static frictional force = 98 × 0.7 N

Static frictional force = 68.6 N is less than 100 N applied  

10 kg block will slide on 40 kg slab and net force on it  

= 100 N - kinetic friction  

=100-(98 \times 0.4)\left(\mu_{\text {kinetic }}=0.4\right)

= 100 - 39.2

= 60.8 N

10 \mathrm{kg} \text { block will slide on } 40 \mathrm{kg} \text { slab with, } \frac{\mathrm{Net} \text { force }}{\text { mass }}

10 \mathrm{kg} \text { block will slide on } 40 \mathrm{kg} \text { slab with }=\frac{60.8}{10}

10 \mathrm{kg} \text { block will slide on } 40 \mathrm{kg} \text { slab with }=6.08 \mathrm{m} / \mathrm{s}^{2}

\text { Frictional force on 40 kg slab by 10 kg block, normal reaction \times \mu_{kinetic } }

Frictional force on 40 kg slab by 10 kg block = 98 × 0.4  

Frictional force on 40 kg slab by 10 kg block = 39.2 N  

40 \mathrm{kg} \text { slab will move with } \frac{\text { frictional force }}{\text { mass }}

40 \mathrm{kg} \text { slab will move with }=\frac{39.2}{40}

40 kg slab will move with = 0.98 \mathrm{m} / \mathrm{s}^{2}

\text { The "resulting action" on the slab is } 0.98 \mathrm{m} / \mathrm{s}^{2}

3 0
3 years ago
Question 8 Unsaved
julia-pushkina [17]
The first one:
Like poles repel each other and opposite poles attract each other
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