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Karo-lina-s [1.5K]
3 years ago
9

You need to prepare a 0.199-mm-diameter tungsten wire with a resistance of 3.09 kÏ. how long must the wire be? the resistivity o

f tungsten is 5.62 à 10-8 Ï·m.
Physics
1 answer:
jekas [21]3 years ago
7 0
<span>1.71x10^3 meters. The resistivity of a conductor with an uniform cross section is expressed as R = pl/A where p = resistivity l = length of conductor A = cross sectional area of conductor. Solving for l gives R = pl/A RA = pl RA/p = l The cross section is defined a A = pi r^2, so A = 3.14159 * (9.95x10^-5 m)^2 A = 3.14159 * 9.90025x10^-9 m^2 A = 3.11025x10^-8 m^2 Now substitute the known values into the formula, giving: RA/p = l 3090 ohm * 3.11025x10^-8 m^2 / 5.62x10^-8 ohm * m = l 1.71009x10^3 m Rounding to 3 significant places gives 1.71x10^3 meters.</span>
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Answer:8.76\times 10^{-3} min^{-1}

Explanation:

Given

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According to Avrami equation

y=1-e^{-kt^n}

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k=constant

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0.3=1-e^{-k(100)^5}

e^{-k(100)^5} =0.7

Taking log both sides

-k\cdot (10^{10}=\ln 0.7

k=3.566\times 10^{-11}

At this Point we want to compute t_{0.5}\ i.e.\ y=0.5

0.5=1-e^{-kt^n}

0.5=e^{-kt^n}

0.5=e^{-3.566\times 10^{-11}\cdot (t)^5}

taking log both sides

\ln 0.5=-3.566\times 10^{-11}\cdot (t)^5

t^5=1.943\times 10^{10}

t=114.2 min

Rate of Re crystallization at this temperature

t^{-1}=8.76\times 10^{-3} min^{-1}

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3 years ago
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