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Bumek [7]
3 years ago
10

An electron (m= 9.11 x 10 ^-31 kg) moves in a circle whose radius is 2.00 x 10^-2 m. If the force acting on the electron is 4.60

x 10^-14 N, what is the speed?
Physics
1 answer:
Rina8888 [55]3 years ago
6 0
Oh wow!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Kepler’s third law states that for all objects orbiting a given body, the cube of the semimajor axis (A) is proportional to the
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Explanation:

Kepler’s third law states that for all objects orbiting a given body, the cube of the semimajor axis (A) is proportional to the square of the orbital period (P).

For each of our planets orbiting the Sun, the relationship between the orbital period and semimajor axis can be represented by the equation as:

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Answer:

Lower

Lower

gsintheta (gsinθ)

Explanation:

The sum of forces resolved parallel to the inclined plane is given by;

F - mgsinθ = 0

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Acceleration is proportional to angle of inclination, thus the lower the angle of the slope, lower the acceleration along the ramp.

therefore, the speed at the bottom of a slope will be lower, (velocity is directly proportional to acceleration) and, consequently, the control will be better.

The acceleration along the ramp, is gsintheta (gsinθ)

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Galina-37 [17]

Answer:

Explanation:

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