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lubasha [3.4K]
3 years ago
13

A monochromatic light passes through a narrow slit and forms a diffraction pattern on a screen behind the slit. As the slit widt

h increases, the diffraction pattern:
O becomes dimmer.
O shrinks with all the fringes getting narrower.
O spreads out with all the fringes getting alternately wider and then narrower.
O remains unchanged.
O spreads out with all the fringes getting wider.
Physics
1 answer:
maw [93]3 years ago
8 0

Answer:

shrinks with all the fringes getting narrower

Explanation:

As the light passes through the slit, the diffraction pattern shrinks, as the waves have more opening to penetrate, and the fringes becomes more narrow as a result of that, The opposite happens as the conditions are reversed.

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A 2.0 kg block is given an initial speed of 8.0 m/s up an incline plane of angle 30° where the coefficient of friction is 0.35.
Korvikt [17]

Answer:

4.1 m

Explanation:

Given :

Mass of the block = m = 2 kg.

Initial velocity = v_{i} = 8 m/s

Angle of the incline = α = 30°

Coefficient of friction = μ = 0.35

Distance moved up the incline is calculated using the work energy theorem.

Work done by the net force =  change in kinetic energy of the object.

Net work = work done by friction + work done by the gravity component.

(- mg sin 30 - μ mg cos 30 ) d = 1/2m v_{f}^{2} - 1/2 m v_{i}^{2}

m cancels out when divided on both sides with m.

- [(9.8 sin 30 - ( 0.35  × 9.8 × cos 30) ] d = 1/2 ( 0² - 8² )

⇒ -7.87 d = -32

⇒ Distance traveled up the incline = d = 4.0658 m = 4.1 m

8 0
4 years ago
Suppose you and a friend are test driving a new car. You drive out of the car dealership and go 10 miles east and then 8 miles s
damaskus [11]

a =12miles

b =10miles

ab =2miles

Explanation:

at first the car is drown out of dealership and went 10 miles east and then 8 miles south

then your friend drives 8 miles west and 6 miles north.

then the distance it flies to get back to dealership is

10²+8 ²=12miles

8²+6²=10miles

12-10= 2 miles

5 0
3 years ago
Cole drives to school from home, starting from rest and accelerating for 10 minutes as he travels 6.0 km to school.
Firlakuza [10]

Explanation:

this is the answer for your question. if you have any doubt.

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3 0
3 years ago
A tank with a volume of 0.150 m3 contains 27.0oC helium gas at a pressure of 100 atm. How many balloons can be blown up if each
jekas [21]

Answer:

884 balloons

Explanation:

Assume ideal gas, since temperature is constant, then the product of pressure and volume is constant.

So if pressures reduces from 100 to 1.2, the new volume would be

V_2 = \frac{P_1V_1}{P_2} = \frac{100*0.15}{1.2} = 12.5 m^2

The spherical volume of each of the balloon of 30cm diameter (15 cm or 0.15 m in radius) is

V_b = \frac{4}{3}\pir^3 = \frac{4}{3}\pi 0.15^3 = 0.014 m^3

The number of balloons that 12.5 m3 can fill in is

V_2/V_b = 12.5 / 0.014 = 884

8 0
3 years ago
Find the magnitude of pressure in Pascal of 150N that acts normally on area. Of 0.25m2
s2008m [1.1K]

Pressure = force/ area

= 150N/ 0.25m^2

= 600Pa

5 0
3 years ago
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