Answer:
The activation energy for this reaction, Ea = 159.98 kJ/mol
Explanation:
Using the Arrhenius equation as:
Where, Ea is the activation energy.
R is the gas constant having value 8.314 J/K.mol
K₂ and K₁ are the rate constants
T₂ and T₁ are the temperature values in kelvin.
Given:
K₂ = 8.66×10⁻⁷ s⁻¹ , T₂ = 425 K
K₁ = 3.61×10⁻¹⁵ s⁻¹ , T₁ = 298 K
Applying in the equation as:
Solving for Ea as:
Ea = 159982.23 J /mol
1 J/mol = 10⁻³ kJ/mol
Ea = 159.98 kJ/mol
Answer:
ratio of the masses of the two enemies = 1.7
Explanation:
Applying the law of conservation of momentum,
Momentum fo Bonzo = Momentum of Ender
mv = m'v'................. Equation 1
Where m = mass of Bonzo, v = velocity of Bonzo, m' = mass of Ender, v' = velocity of Ender
m/m' = v'/v............... Equation 2
Where m/m' = ratio of the masses of the two enemies
Given: v = 2.0 m/s, v' = 3.4 m/s
Substitute into equation 2
m/m' = 3.4/2
m/m' = 1.7
Hnece, ratio of the masses of the two enemies = 1.7
I think B would be the best answer
