How do you factor 12j^2k - 36j^6k^6 12j^2?

What is the equation of the graphed line?

Rufina [12.5K]

Line crosses the y-axis, b, called the y-intercept. when graphing, put thisequation into "y = " form to easily read graphing information. horizontallines have a slope of zero - they have "run", but no "rise" -- all of the y values are 3.

7 0

4 years ago

Consider the vectors u <-4,7> and v= <11,-6>

coldgirl [10]

Answer:

u + v = <7 , 1>

║u + v║ ≅ 7

Step-by-step explanation:

* Lets explain how to solve the problem

- We can add two vector by adding their parts

∵ The vector u is <-4 , 7>

∵ The vector v is <11, -6>

∴ The sum of u and v = <-4 , 7> + <11 , -6>

∴ u + v = <-4 + 11 , 7 + -6> = <7 , 1>

∴ The sum u and v is <7 , 1>

* u + v = <7 , 1>

- The magnitude of the resultant vector = √(x² + y²)

∵ x = 7 and y = 1

∵ ║u + v║ means the magnitude of the sum

∴ The magnitude of the resultant vector = √(7² + 1²)

∴ The magnitude of the resultant vector = √(49 + 1) = √50

∴ The magnitude of the resultant vector = √50 = 7.071

* ║u + v║ ≅ 7

4 0

4 years ago

Joe measured a brick using a ruler with centimeters and got 9 cm. He then measured the same brick using a ruler with millimeters

Natasha_Volkova [10]

Answer:

yes, the measures are equivalent because the formula for cm to mm is times 10. 9 times 10 is 90.

Step-by-step explanation:

hope this helps! pls mark brainliest!

8 0

3 years ago

The equation for line t can be written as y = 4x - 8. Line u, which is perpendicular to line t,

xeze [42]

Here, we are required to determine the equation of the line u which is perpendicular to the line t and passes through the point (8,8).

The equation of the line u is;. y = (-x/4) + 10.

First, the product of the slope of 2 perpendicular lines is negative 1 i.e -1.

M1 × M2 = -1

From observation, the slope of line t given by y = 4x - 8 is equal to 4.

Therefore, since M1 = 4,
Then, M2 = -1/4

To get the equation of a line,

Slope, M2 = (y - y1)/(x - x1)

where M2 = -1/4 , y1 = 8 and x1 = 8.

Therefore, -1/4 = (y - 8)/(x - 8).

Therefore, -x + 8 = 4y -32

Therefore, 4y = -x + 40.

Ultimately, the equation of the line u is ;

y = (-x/4) + 10.

Read more:

brainly.com/question/19506739

8 0

3 years ago

For the function given below, find a formula for the Riemann sum obtained by dividing the interval [0,5] into n equal subinterva

sergij07 [2.7K]

Given

we are given a function

$f(x)=x^2+5$

over the interval [0,5].

Required

we need to find formula for Riemann sum and calculate area under the curve over [0,5].

Explanation

If we divide interval [a,b] into n equal intervals, then each subinterval has width

$\Delta x=\frac{b-a}{n}$

and the endpoints are given by

$a+k.\Delta x,\text{ for }0\leq k\leq n$

For k=0 and k=n, we get

$\begin{gathered} x_0=a+0(\frac{b-a}{n})=a \\ x_n=a+n(\frac{b-a}{n})=b \end{gathered}$

Each rectangle has width and height as

$\Delta x\text{ and }f(x_k)\text{ respectively.}$

we sum the areas of all rectangles then take the limit n tends to infinity to get area under the curve:

$Area=\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\Delta x.f(x_k)$

Here

$f(x)=x^2+5\text{ over the interval \lbrack0,5\rbrack}$ $\Delta x=\frac{5-0}{n}=\frac{5}{n}$ $x_k=0+k.\Delta x=\frac{5k}{n}$ $f(x_k)=f(\frac{5k}{n})=(\frac{5k}{n})^2+5=\frac{25k^2}{n^2}+5$

Now Area=

$\begin{gathered} \lim_{n\to\infty}\sum_{k\mathop{=}1}^n\Delta x.f(x_k)=\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\frac{5}{n}(\frac{25k^2}{n^2}+5) \\ =\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\frac{125k^2}{n^3}+\frac{25}{n} \\ =\lim_{n\to\infty}(\frac{125}{n^3}\sum_{k\mathop{=}1}^nk^2+\frac{25}{n}\sum_{k\mathop{=}1}^n1) \\ =\lim_{n\to\infty}(\frac{125}{n^3}.\frac{1}{6}n(n+1)(2n+1)+\frac{25}{n}n) \\ =\lim_{n\to\infty}(\frac{125(n+1)(2n+1)}{6n^2}+25) \\ =\lim_{n\to\infty}(\frac{125}{6}(1+\frac{1}{n})(2+\frac{1}{n})+25) \\ =\frac{125}{6}\times2+25=66.6 \end{gathered}$

So the required area is 66.6 sq units.

3 0

1 year ago