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3 years ago

What is [4 –4–2] – [4 –3 5]

Mathematics

2 answers:

GrogVix [38]3 years ago

7 0

Look at the picture it will show you the answer and give you a step by step explanation.

Snezhnost [94]3 years ago

5 0

I believe the answer is 29

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What line would be parallel to 8x-2y=7 with a point of 12,1

SOVA2 [1]

Answer:

$y = 4x - 47$

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

$y = mx + b$

In which m is the slope and b is the y-intercept.

Parallel lines:

When two lines are parallel, they have the same slope.

8x-2y=7

Placing into the format, we have thtt:

$2y = 8x - 7$

$y = 4x - \frac{7}{2}$

Slope of 4.

This means that the desired line has the following equation:

$y = 4x + b$

Point of (12,1)

This means that when $x = 12, y = 1$

We use this to find b.

$y = 4x + b$

$1 = 48 + b$

$b = -47$

So, the line has the equation:

$y = 4x - 47$

7 0

3 years ago

Mr. Standford’s greenhouse has the dimensions shown. The volume of the greenhouse is 90 cubic yards. Find the missing dimension

salantis [7]

Hey read the image I have attached. Ignore what I am typing here I need to type 20 characters.

3 0

4 years ago

In a study of pleas and prison sentences, it is found that 6060% of the subjects studied were sent to prison. Among those sent

Dovator [93]

Answer:

a. 40 %

b. 34.3 % ( approx )

Step-by-step explanation:

Let S is the event of the subjects studied that were sent to prison,

S' is the event of the subjects studied that won't sent to prison,

G is the event of pleading guilty,

G' is the event of not pleading guilty,

According to the question,

P(S) = 60% = 0.6 ⇒ P(S') = 1 - P(S) = 1 - 0.6 = 0.4,

P(S∩G) = 46% of 60% = 0.46 × 0.60 = 0.276,

P(S'∩G) = 36% of 40% = 0.36 × 0.40 = 0.144,

P(G) = P(S∩G) + P(S'∩G) = 0.276 + 0.144 = 0.42

a. The of getting someone who was not sent to prison, P(S') = 0.4,

b. the probability that this person was not sent to prison when it is given that the subject entered a guilty plea,

$P(\frac{S'}{G})=\frac{P(S'\cap G)}{P(G)}=\frac{0.144}{0.42}\approx 0.343=34.3\%$

7 0

4 years ago

Given that , the _____ justifies the conclusion that ∆ABD ≅ ∆AEC.

trasher [3.6K]

AAS Postulate

It is given that CE = BD so we know "S" (representing side) has to be in the three letter postulate.
It is also given that angle DBA and angle CEA are right angles, so therefore they are congruent. Now we know that an "A" must also be in the postulate.

Lastly, we know that the triangles have a second angle, EAB, in common because they share it overlappingly. So there must be another "A" in the postulate.

Now we need to look at the order in which it is presented. The order follows Angle, Angle, Side so the postulate must be the AAS postulate. Hope this helps!

3 0

3 years ago

Read 2 more answers

The height, in feet, after x seconds of an object launched straight up can be found by the function h(x)=−16x2+v0x+h0, where v0

jok3333 [9.3K]

If you knew calculus this problem would take like 2 seconds, but since we are working with maybe Algebra 2, you have to use the equation as it is and find where h(x) is 0, because that is the height of something when it hits the ground. Meaning, you have to factor this and solve it for x. Here's your equation:
h(x) = -16x^2 + 60x +16. Use the quadratic formula to find that the values for x are -.25 and 4 seconds. Of course time cannot ever carry a negative value, so the answer is 4 seconds. It takes the ball 4 seconds to hit the ground.

7 0

4 years ago