All categories

3 years ago

A laboratory procedure calls for making 410.0mL of a 1.2M NaNO3 solution.

Chemistry

2 answers:

il63 [147K]3 years ago

8 0

Answer:

The mass of NaNO3 needed is 41.82 grams

Explanation:

The molarity of a compound is defined as the number of moles of the substance in 1 liter of solution. Then, from this definition and using a rule of three, it is possible to calculate the amount of moles present in 410 ml. Remember that 1 L = 1000 ml, then 410 ml = 0.410 L

If 1.2 moles of NaNO3 are present in 1 L of solution, how many moles are in 0.410 L of solution?

$moles of NaNO3=\frac{0.410 L* 1.2 moles}{1 L}$

moles of NaNO3=0.492

And the molar mass of the compound can be calculated by adding the atomic mass of each element present in the compound, taking into account the present amount of each:

Na: 23 g/mol
N: 14 g/mol
O: 16 g/mol

mass of the compound NaNO3= 23 g/mol + 14 g/mol + 16*3 g/mol

mass of the compound NaNO3=85 g/mol

Then, a new rule of three can be applied to calculate the mass of NaNO3 sodium nitrate needed: if in 1 mole they represent 85 grams of sodium nitrate, how many moles are in 0.492 moles?

$necessary mass of NaNO3=\frac{0.492 moles*85 grams}{1 mol}$

necessary mass of NaNO3=41.82 grams

The mass of NaNO3 needed is 41.82 grams

ryzh [129]3 years ago

6 0

Molar mass NaNO3 = 85 g/mol

Volume in liters: 410.0 mL / 1000 => 0.41 L

mass = M x molar mass x V

mass = 1.2 x 85 x 0.41

mass = 41.82 g of NaNO3

You might be interested in

Diethyl ether (C2H5 )2O vaporizes at room temperature. If the vapor exerts a pressure of 233 mm Hg in a flask at 25 °C, what is

Svet_ta [14]

Answer: The density of the given vapor is 0.939 g/L.

Explanation:

Given: Pressure = 233 mm Hg (1 mm Hg = 0.00131579 atm) = 0.31 atm

Temperature = $25^{o}C$ = (25 + 273) K = 298 K

According to the ideal gas equation,

$PV = \frac{m}{M}RT$

where,

P = pressure

V = volume

m = mass

M = molar mass

R = gas constant = 0.0821 L atm/mol K

T = temperature

This formula can be re-written as follows.

$PM = \frac{m}{V}RT$ (where, $Density = \frac{mass (m)}{Volume (V)}$ )

Hence, formula used to calculate density of diethy ether (molar mass = 74.12 g/mol) vapor is as follows.

$d = \frac{PM}{RT}$

Substitute values into the above formula as follows.

$d = \frac{PM}{RT}\\= \frac{0.31 atm \times 74.12 g/mol}{0.0821 L atm/mol K \times 298 K}\\= \frac{22.9772}{24.4658}\\= 0.939 g/L$

Thus, we can conclude that the density of the given vapor is 0.939 g/L.

6 0

3 years ago

Dichloromethane contains strong carbon - hydrogen and carbon- chlorine bonds. Despite the presence of these strong bonds. dichlo

const2013 [10]

Answer:

vot. tofu p f focpxe9d3dotc

Explanation:

circeicirct pupdtoxkr

4 0

3 years ago

Balance H2 + O2 - H2O

sweet-ann [11.9K]

Currently in this equation, you have 2 hydrogen atoms and 2 oxygen atoms on the left, and then 2 hydrogen atoms and 1 oxygen atom on the right. To balance, you would need to even out the oxygens, so we can first place a 2 in front of H2O to get:
H2 + O2 -> 2H2O

Now, however, you can see that we have too many hydrogen atoms on the right, so to get the final answer, we add a 2 in front of hydrogen on the left:

2H2 + O2 -> 2H2O

I hope this helps!

3 0

3 years ago

Read 2 more answers

Choose the example that is a protein: •bread •enzyme •ORNA •sugar

taurus [48]

Answer:

I think bread is the answer

4 0

4 years ago

You are analyzing a compound in a laboratory. you find that it is made up of carbon, hydrogen, and oxygen in a ratio of two hydr

kotegsom [21]

Carbohydrates because carbohydrate is a molecule that contains carbon, hydrogen and oxygen usually in a ratio of two hydrogen atoms for each carbon atom. Carbohydrates are also known as saccharides or carbs.They are basically sugar or starches.

5 0

3 years ago