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3 years ago

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Dichloromethane contains strong carbon - hydrogen and carbon- chlorine bonds. Despite the presence of these strong bonds. dichlo

romethane is a liquid...explain why??
can some one help me ??
50 points

1 answer:

const2013 [10]3 years ago

4 0

Answer:

vot. tofu p f focpxe9d3dotc

Explanation:

circeicirct pupdtoxkr

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A chemist adds 255 .0 mL of a M copper(II) sulfate solution to a reaction flask. Calculate the mass in grams of copper(II) sulfa

melomori [17]

Answer:

The correct answer is 40.7 grams.

Explanation:

Based on the given information, the volume of copper sulfate added to the solution is 255 ml or 0.255 L. The molarity of copper sulfate is not given, so let us consider it to be 1 M, which can also be written as 1 moles per liter.

The moles of copper sulfate can be determined by using the formula,

Moles = Molarity * Volume in Liters

Moles of CuSO4 = 1 moles/Liter * 0.255 L

Moles of CuSO4 = 0.255 moles

The mass of CuSO4 added in the solution will be,

Mass of CuSO4 = Moles * Molecular mass

= 0.255 moles * 159.609 grams per mole

= 40.7 grams.

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2 years ago

Iodine-131 is a beta emitter used as a tracer in radio immunoassays in biological systems. It follows first order kinetics. The

allsm [11]

<u>Answer:</u> The amount of Iodine-131 remain after 39 days is 0.278 grams

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction = 8.04 days

Putting values in above equation, we get:

$k=\frac{0.693}{8.04days}=0.0862days^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.0862days^{-1}$

t = time taken for decay process = 39 days

$[A_o]$ = initial amount of the sample = 8.0 grams

[A] = amount left after decay process = ?

Putting values in above equation, we get:

$0.0862=\frac{2.303}{39}\log\frac{8.0}{[A]}$

$[A]=0.278g$

Hence, the amount of Iodine-131 remain after 39 days is 0.278 grams

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2 years ago

குளோரோ பென்சீனை எவ்வாறு பீனால் ஆக மாற்றுவது<br>

Assoli18 [71]

Explanation:

dows method

பதில்: டோவின் முறை

சோடியம் பினாக்ஸைடு அயனியைப் பெற, எதிர்வினை குளோரோபென்சீன் 623K மற்றும் 300atm வெப்பநிலையில் அக்வஸ் சோடியம் ஹைட்ராக்சைடுடன் உயர்த்தப்படுகிறது. சோடியம் பினாக்ஸைடு அயன் அடுத்த கட்டத்தின் போது நீர்த்த எச்.சி.எல் உடன் இணைக்கப்படுகிறது, இது இறுதி தயாரிப்பை பினோலாக உருவாக்குகிறது

by jus dot com

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2 years ago

Predict the shape of the molecule around the

QveST [7]

It can’t be linear or tetrahedral it’s either trogons planar or bent and trogons has the word tri which stands for three so that’s not the answer the answer is bent and through process of elimination I did this thank you from me

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2 years ago

A sample of neon gas at a pressure of 0.609 atm and a temperature of 25.0 °C, occupies a volume of 19.9 liters. If the gas is co

Alona [7]

Answer:

The pressure of the gas sample will be 0.954 atm.

Explanation:

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. That is, if the pressure increases, the volume decreases; conversely if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

o P * V = k

To determine the change in pressure or volume during a transformation at constant temperature, the following is true:

P1 · V1 = P2 · V2

That is, the product between the initial pressure and the initial volume is equal to the product of the final pressure times the final volume.

In this case:

P1= 0.609 atm
V1= 19.9 L
P2=?
V2= 12.7 L

Replacing:

0.609 atm* 19.9 L= P2* 12.7 L

Solving:

$P2=\frac{0.609 atm* 19.9 L}{12.7 L}$

P2= 0.954 atm

<u><em>The pressure of the gas sample will be 0.954 atm.</em></u>

<u><em></em></u>

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3 years ago