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zvonat [6]
3 years ago
11

Dichloromethane contains strong carbon - hydrogen and carbon- chlorine bonds. Despite the presence of these strong bonds. dichlo

romethane is a liquid...explain why??
can some one help me ??
50 points​
Chemistry
1 answer:
const2013 [10]3 years ago
4 0

Answer:

vot. tofu p f focpxe9d3dotc

Explanation:

circeicirct pupdtoxkr

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What is the ROUNDED atomic number for this elements?
denis-greek [22]
Sodium/Atomic number

11

Gold/Atomic number

79
Potassium/Atomic number

19

Silicon/Atomic number

14




8 0
3 years ago
What is the significance of "Er" in the diagram?
Drupady [299]

Answer:

The significance of "Er" in the diagram is :

B.) Threshold energy for reaction

Explanation:

Threshold energy : It is total amount of energy required by the reactant molecule to reach the transition state .

Activation energy : It is the excess energy absorbed by the molecules to reach the transition state.

<u>Activation Energy = Threshold Energy - Average Kinetic Energy</u>

<u>This means Activation energy decreases on increasing kinetic energy</u>

On increasing Temperature average kinetic energy of the molecule increases which reduces the activation energy and the reaction occur faster in that case.

Catalyst also reduces the Activation energy.

<u>Er = Threshshold energy for reaction at 30 degree</u>

<u>Ea = Activation Energy</u>

<u>The given figure shows that the threshold energy decreases on increasing the temperature</u>

<u>Only the molecule having energy greater than Er can react to form product</u>

3 0
3 years ago
Read 2 more answers
Can someone please check my answer??!!!
Ksenya-84 [330]

Answer:

I think its correct

5 0
3 years ago
Read 2 more answers
Protons are positively charged and repel other protons. Which other particle is found in the nucleus and separates protons so th
Leto [7]
Neutrons which doesn't have any charge
6 0
3 years ago
Read 2 more answers
A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the
Damm [24]

Answer:

See solution.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:

\%  M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\%  =\frac{m_M}{m_M+32.00}*100 \%

Thus, we solve for the molar mass of the metal to obtain:

59.93\% (m_M+32.00) =m_M*100 \%\\\\m_M*59.93\% +1917.76\% =m_M*100 \%\\\\m_M=47.86g/mol

For the subsequent problems, we proceed as follows:

a.

4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2

b.

0.400molH_2S*\frac{2molH}{1molH_2S}*\frac{6.022x10^{23}atomsH}{1molH}=4.82x10^{23}atomsH

c.

0.235gNH_3*\frac{1molNH_3}{17.03gNH_3} *\frac{3molH}{1molNH_3}*\frac{6.022x10^{23}atomsH}{1molH}=2.49x10^{22}atomsH

Regards!

7 0
3 years ago
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