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Solnce55 [7]
3 years ago
9

Define distance and displacement with illustration​

Physics
1 answer:
Deffense [45]3 years ago
3 0

Answer:

<h2><em>Distance</em></h2>

<em>The </em><em>length</em><em> </em><em>of </em><em>the </em><em>actual </em><em>path </em><em>travelled by </em><em>a </em><em>body </em><em>is </em><em>called </em><em>distance </em><em>travelled </em><em>by </em><em>a </em><em>body.It </em><em>is </em><em>a </em><em>scalar </em><em>Quantity.</em><em>I</em><em>t</em><em> </em><em>is </em><em>measured</em><em> </em><em>in </em><em>meter(</em><em>m)</em><em> </em><em>in </em><em>SI </em><em>system.</em>

<h2><em>Displacement</em></h2>

<em>The </em><em>shortest </em><em>distance</em><em> </em><em>from </em><em>initial </em><em>position</em><em> </em><em>to </em><em>the </em><em>final </em><em>position</em><em> </em><em>of </em><em>a </em><em>body </em><em>is </em><em>called </em><em>displacement</em><em> </em><em>of </em><em>the </em><em>body.It </em><em>is </em><em>a </em><em>vector</em><em> </em><em>Quantity.</em><em>I</em><em>t</em><em> </em><em> </em><em>is </em><em>measured</em><em> </em><em>in </em><em>meter(</em><em>m)</em><em> </em><em>in </em><em>SI </em><em>system.</em><em>.</em>

<em>Please </em><em>see </em><em>the </em><em>attached </em><em>picture.</em><em>.</em><em>.</em>

<em>It </em><em>is </em><em>the </em><em>example </em><em>of </em><em>distance </em><em>and </em><em>displacement.</em><em>.</em><em>.</em><em>.</em>

<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>

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A mass is oscillating on the end of a spring. The distance, y, of the mass from its equilibrium point is given by the formula y=
dybincka [34]

Answer:

(a.) 4z

(b.) 4w

Explanation:

From the equation y=4zcos(8πwt), where z and w are positive constants.

Comparing this equation to the equation of a wave y = Acos(Wt), where A is the amplitude (largest distance from equilibrium) and W is the angular frequency (W=2πf)

(a.) Comparing our wave equation with the given equation, we see that A = 4z in this case (furthest distance of the mass from equilibrium)

(b.) Comparing similarly we can see from our given equation that angular frequency W =8πw we also know that W = 2πf from our wave equation, therefore 2πf = 8πw

Solving for f we have f = 8πw÷2π

f = 4w (Proves our second answer because the frequency is the number of oscillations completed per second)

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3 years ago
A train is traveling down a straight track at 20. m/s when the engineer applies the brakes, resulting in an acceleration of -1.0
Kipish [7]

Answer:

The answer to your question is: d = 0 m, it does not move

Explanation:

Data

vo = 20 m/s

a = -1 m/s2

t = 40 s

d = ?

Formula

d = vot + (1/2)at²

Substitution

d = (20)(40) + (1/2)(-1)(40)²

d = 800 - 800

d = 0 m                                  It suggest that it does not move.

                                       I hope it can help you

7 0
3 years ago
Willy the heat Willy the Lol​
mr_godi [17]

Explanation:

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4 0
3 years ago
Read 2 more answers
Bruce has a momentum of 430kg m/s and is running at 7.8m/s. What is Bruce's mass?
ryzh [129]

Answer:

55.128kg

Explanation:

P= m×v

or, m=P/v = 430/7.8 = 55.128 kg

7 0
4 years ago
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Two astronauts, each having a mass of 74 kg, are connected by a 8.53 m rope of negligible mass. They are isolated in space, orbi
AveGali [126]

Answer:

a) 2575 kgm²/s

b) 1.23 kJ

c) 0.478 rad/s

Explanation:

Given

Mass of astronauts, m = 74 kg

Length of rope, l = 8.53 m

Speed of orbit, v = 4.08 m/s

L = m1v1.x1(i) + m2v2.x2(i) = 2mv(d/2)

Thus, L = 2.m.v.(d/2)

L = 2 * 74 * 4.08 * (8.53/2)

L = 2 * 74 * 4.08 * 4.265

L = 2575.38 kgm²/s

Rotational Energy of the system

K(i) = 1/2m1v1(i)² + 1/2m2v2(i)²

K(i) = 2(1/2) * 74 * 4.08²

K(i) = 74 * 16.6464

K(i) = 1231.83 J = 1.23 kJ

Angular momentum is conserved, thus, angular velocity, w = v/r

w = 4.08 / 8.53

w = 0.478 rad/s

7 0
3 years ago
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