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liubo4ka [24]
3 years ago
14

What's is the answer to 15n-19n

Mathematics
1 answer:
Art [367]3 years ago
8 0

Answer:

-4n

Step-by-step explanation:

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Answer: 2.2= 11/5 or 1 1/5
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There are 49 flowers to split evenly between 7 vases. How many flowers go in each vase?
dexar [7]
49 divided by 7 is 7. 

The answer is 7 flowers in each vase.
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I NEED HELP ASAPPPP
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A set of numbers satisfies Benford’s Law if the probability of a number starting with digit d is P(d) = log(d + 1) – log(d).
irakobra [83]

Interpreting the graph and the situation, it is found that the values of d that can be included in the solution set are 1 and 4.

----------------------

  • According to Benford's law, the probability of a number starting with digit is d is:

P(d) = \log{(d + 1}} - \log{d}

  • A number can start with 10 possible digits, ranging from 1 to 9, which are all integer digits.
  • Thus, d can only assume integer digits.
  • In the graph, the solution is d < 5.
  • The integer options for values of d are 1 and 4.
  • For the other options that are less than 5, they are not integers, so d cannot assume those values.

A similar problem is given at brainly.com/question/16764162

8 0
2 years ago
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At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

3 0
3 years ago
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