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3 years ago

What's is the answer to 15n-19n

Mathematics

1 answer:

Art [367]3 years ago

8 0

Answer:

-4n

Step-by-step explanation:

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Please help this is algebra 1 problem is in the picture

Naddika [18.5K]

Answer:

0,1,2,3,4,5

Step-by-step explanation:

You can not buy more than 5 books because you'd have a negative amount of money. So 0,1,2,3,4,5 are the possible values for b.

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3 years ago

Kiyo bought a pizza for $12.75 and four medium drinks at Pauli´s pizza. Define a variable and write an expression to represent t

Vlada [557]

12.75+4x

Answer: 24.75

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3 years ago

GEOMETRY Find the perimeter of the regular polygon. 3(x - 1) 5x - 6

viktelen [127]

Answer:

7.5

Step-by-step explanation:

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3 years ago

Use two unit multipliers to convert 628 kilometers to centimeters

irina [24]

Using two unit multiplier 628 km is equal to 62800000 cm

Solution:

628 kilometer to centimeter

We will go from kilometers to meters to centimeters.

Start by putting 628 km over 1:

$\frac{628 km}{1}$

We want to get rid of km and bring in m.

We know that 1000 m = 1 km.

Since km is in the numerator, we will make the first unit multiplier by putting 1 km in the denominator and 1000 m in the numerator, so the km will cancel. So we multiply by the unit multiplier,

$\frac{628 km}{1} \times \frac{1000m}{1km}$

Now the km's will cancel:

$\frac{628}{1} \times \frac{1000m}{1}$

Now we want to get rid of m and bring in cm.

We know that 100 cm = 1 m.

Since meter is in the numerator, we will make the first unit multiplier by putting 1 meter in the denominator and 100 cm in the numerator, so the meter's will cancel. So we multiply by the unit multiplier

$\frac{100cm}{1m}$

$\frac{628}{1} \times \frac{1000m}{1} \times \frac{100cm}{1m}$

We cancel the m's and we end up with:

$628 \times 1000 \times 100 cm$

= 62800000 cm

Thus 628 km is equal to 62800000 cm

5 0

4 years ago

Please hurry I’m in a timed test!!!! If sintheta>0, and tan theta<0 then:

Trava [24]

Answer: The angle is in the second quandrant

Step-by-step explanation:

If sin of theta is greater than 0, the angle theta has to be in either the first or second quandrant. If tangent of theta is less than 0, it cannot be in the first or third quandrant. Therefore, we know the angle is in the second quandrant.

5 0

3 years ago