Fe=k|q1q2| / r^2
(k is the electrostatic constant which has a value of 8.99x10^9 Nm^2/c^2, r is the distance between the charges and q is the quantity of the charges.)
Answer:
Yes
Explanation:
The velocity measured by Jennifer and Johnny is

The actual velocity is

We can calculate the % error of the students measurement as follows:

Which is lower than the 2.5% maximum error required, so the two students will pass the test.
Answer: 11,100 ft/s^2
1) Constant acceleration=> uniformly accelerated motion.
2) Formula for uniformly accelerated motion:
Vf = Vo + at
3) Data:
Vo = 1,100 ft/s
a = 1,000 ft/s^2
t = 10.0 s
4) Solution:
Vf = 1,100 ft/s + 1,000 ft/s^2 * 10.0 s = 1,100 ft/s + 10,000 ft/s
Vf = 11,100 ft/s