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AURORKA [14]
3 years ago
7

n a level football field a football is projected from ground level. It has speed 9.0 m/sm/s when it is at its maximum height. It

travels a horizontal distance of 40.0 mm. Neglect air resistance. Part A How long is the ball in the air
Physics
1 answer:
Pani-rosa [81]3 years ago
4 0

Answer:

T = 0.225 s

Explanation:

The speed of a projectile at the highest point of its motion is the horizontal speed of the projectile. Considering the horizontal motion with negligible air resistance, we can use the following formula:

v_x = RT\\\\T = \frac{v_x}{R}

where,

T = Total time of ball in air = ?

R = Horizontal distance covered = 40 m

v_x = horizontal speed = 9 m/s

Therefore,

T = \frac{9\ m/s}{40\ m}

<u>T = 0.225 s</u>

You might be interested in
A simple pendulum has a period of 3.45 second, when the length of the pendulum is shortened by 1.0m, the period is 2.81 second c
den301095 [7]

Answer:

Original length = 2.97 m

Explanation:

Let the original length of the pendulum be 'L' m

Given:

Acceleration due to gravity (g) = 9.8 m/s²

Original time period of the pendulum (T) = 3.45 s

Now, the length is shortened by 1.0 m. So, the new length is 1 m less than the original length.

New length of the pendulum is, L_1=L-1

New time period of the pendulum is, T_1=2.81\ s

We know that, the time period of a simple pendulum of length 'L' is given as:

T=2\pi\sqrt{\frac{L}{g}}-------------- (1)

So, for the new length, the time period is given as:

T_1=2\pi\sqrt{\frac{L_1}{g}}------------ (2)

Squaring both the equations and then dividing them, we get:

\dfrac{T^2}{T_1^2}=\dfrac{(2\pi)^2\frac{L}{g}}{(2\pi)^2\frac{L_1}{g}}\\\\\\\dfrac{T^2}{T_1^2}=\dfrac{L}{L_1}\\\\\\L=\dfrac{T^2}{T_1^2}\times L_1

Now, plug in the given values and calculate 'L'. This gives,

L=\frac{3.45^2}{2.81^2}\times (L-1)\\\\L=1.507L-1.507\\\\L-1.507L=-1.507\\\\-0.507L=-1.507\\\\L=\frac{-1.507}{-0.507}=2.97\ m

Therefore, the original length of the simple pendulum is 2.97 m

4 0
3 years ago
The maximum current output of a 60 ω circuit is 11 A. What is the rms voltage of the circuit?
bezimeni [28]

Answer:

660V

Explanation:

V=IR

V=11×60

=660V

hope this helps

please like and Mark as brainliest

8 0
3 years ago
On a drive from one city to? another, victor averaged 39 mph. if he had been able to average 72 ?mph, he would have reached his
PilotLPTM [1.2K]
Let the unknown distance be xmiles
x/39-x/72=11hr
72x-39x/2808=11hr
33x/2808=11
33x= 30888
x=936miles
U can substitue back to check
at speed of 72mph, he would need 936/72=13hrs
at speed of 39mph, he would need 936/39=24hr
the difference is 24-13=11
5 0
3 years ago
A lamp has a current of 2.0 amperes at 6.0 volts. What is the resistance of lamp?
kifflom [539]

Answer: B 3.0

Explanation:

5 0
2 years ago
Represent 7468 N with SI units having an appropriate prefix. Express your answer to four significant figures and include the app
sergeinik [125]

Answer:

7.468 kN

Explanation:

Here the force of 7468 Newton is given.

Some of the prefixes of the SI units are

kilo = 10³

Mega = 10⁶

Giga = 10⁹

The number is 7468.0

Here, the only solution where the number of significant figures is kilo

1 kilonewton = 1000 Newton

1\ Newton=\frac{1}{1000}\ kilonewton

\\\Rightarrow 7468\ Newton=\frac{7468}{1000}\ kilonewton\\ =7.468\ kilonewton

So 7468 N = 7.468 kN

3 0
3 years ago
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