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AURORKA [14]
2 years ago
7

n a level football field a football is projected from ground level. It has speed 9.0 m/sm/s when it is at its maximum height. It

travels a horizontal distance of 40.0 mm. Neglect air resistance. Part A How long is the ball in the air
Physics
1 answer:
Pani-rosa [81]2 years ago
4 0

Answer:

T = 0.225 s

Explanation:

The speed of a projectile at the highest point of its motion is the horizontal speed of the projectile. Considering the horizontal motion with negligible air resistance, we can use the following formula:

v_x = RT\\\\T = \frac{v_x}{R}

where,

T = Total time of ball in air = ?

R = Horizontal distance covered = 40 m

v_x = horizontal speed = 9 m/s

Therefore,

T = \frac{9\ m/s}{40\ m}

<u>T = 0.225 s</u>

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A 50.0-g ball traveling at 25.0 m/s bounces off a brick wall and
liubo4ka [24]

Answer:

13,400 m/s²

Explanation:

Average acceleration is the change in velocity over time:

a = Δv / t

a = (22.0 m/s − (-25.0 m/s)) / 0.00350 s

a = 13,400 m/s²

4 0
3 years ago
how fast will and in what direction will a 20kg object accelerate if one force pushes at a 30 degree angle and another pushes at
DiKsa [7]

Answer:

|a|=2.83\ m/s^2

\theta=75^o

Explanation:

<u>Net Force And Acceleration </u>

The Newton's second law relates the net force applied on an object of mass m and the acceleration it aquires by

\vec F_n=m\vec a

The net force is the vector sum of all forces. In this problem, we are not given the magnitude of each force, only their angles. For the sake of solving the problem and giving a good guide on how to proceed with similar problems, we'll assume both forces have equal magnitudes of F=40 N

The components of the first force are

\vec F_1=

\vec F_1=\ N

The components of the second force are

\vec F_2=

\vec F_2=\ N

The net force is

\vec F_n=

\vec F_n=\ N

The magnitude of the net force is

|F_n|=\sqrt{14.64^2+54.64^2}

|F_n|=\sqrt{3200}=56.57\ N

The acceleration has a magnitude of

\displaystyle |a|=\frac{|F_n|}{m}

\displaystyle |a|=\frac{56.57}{20}

|a|=2.83\ m/s^2

The direction of the acceleration is the same as the net force:

\displaystyle tan\theta=\frac{54.64}{14.64}

\theta=75^o

5 0
2 years ago
A worker pushes a box across the floor to the right at a constant speed with a force of 25N. What can you conclude about the box
kotykmax [81]

Answer:

C. Friction between the box and the floor is 25N to the left

Explanation:

7 0
2 years ago
Read 2 more answers
What is pitch related to?
Jlenok [28]
Pitch is related to frequency
7 0
3 years ago
If the period of the pendulum is tripled, what is the length of the string increased by?
Nitella [24]
The period of the pendulum doesn't determine the length of the string. 
It's the other way around.

The period of the pendulum is proportional to the square root of its length.
So if you want to triple the period, you have to make the string nine times
as long as it is now.
7 0
3 years ago
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