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drek231 [11]
3 years ago
6

Calculate the root mean square velocity of F2,Cl2, and Br2 at 304 K .

Chemistry
1 answer:
Artist 52 [7]3 years ago
5 0
<span>The root mean square velocity of gas molecules as a function of temperature is (M is molecular weight): 
v²rms = 3RT/M, 
and kinetic energy is given by: 
KE = ½Mv ² 
We can make the substitution: 
KE = ½M3RT/M, or 
KE = (3/2)RT. 
Notice the molecular weight variable is gone; that means the answer will be the same for F2, Cl2, and Br2: 
KE = (3/2) (8.314 J/K*mole) (290 K) = 3617 J/mole.</span>
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Answer: 1.46moles

Explanation:

Applying PV= nRT

P= 1atm, V= 32.6L, R= 0.082, T = 273K

Substitute and simplify

1×32.6/(0.082×273)=n

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You are given a liquid. Briefly describe the steps you would take to show whether it is a pure substance or a homogeneous mixtur
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Answer:

By using any one technique like boiling, distillation, condensation ,etc , one can be used to distinguish between a pure substance and a homogeneous mixture.

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The forces that are existing between molecules are known as intermolecular forces. These forces which are weaker than ionic and covalent bonds are classified into three types'

--> dipole-dipole attraction

--> VAN DER WAALS FORCES and

--> hydrogen bonding.

Van Der Waals forces was postulated by a Dutch physicist known as Van Der Waals. He postulated the existence of weak, short-range forces of attraction, which are independent of normal bonding forces, between non-polar molecules. He came to this conclusion after studying the behaviour of real gases at low temperatures and high pressures that:

--> electrons in a non-polar molecule such as hydrogen are close to one nucleus as to the other, although momentary concentration at one end of the molecule may occur,

--> this momentary concentration of electron cloud on one side create a temporary dipole in the hydrogen molecule, that is, one side of the molecule acquires a partial negative charge while the other side acquires a partial positive charge of equal magnitude,

--> the temporary dipole induces a similar dipole in an adjacent molecule,

--> this results in a temporary dipole-induced dipole attraction between the positive and negative ends of the adjacent molecules.

This is how weak Van Der Waals forces are set up. Therefore, option C is CORRECT which states that VAN DER WAALS forces hold molecules together by inducing temporary dipoles that attract each other.

Learn more about Van Der Waals forces here:

brainly.com/question/11457190

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