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2 years ago

Which of the following is a reasonable ground-state electron configuration?

Chemistry

2 answers:

sladkih [1.3K]2 years ago

6 0

The reasonable ground-state electron configuration is: 1s2 2s2 2p6 3s2 3p6 4s2 4d8

klasskru [66]2 years ago

3 0

Answer:

b) 1s2 2s2 2p6 3s2 3p6 4s2 4d8

Explanation:

Electron configuration of an atom is given based on the Aufbau principle which states that electrons are arranged in orbitals such that the lower energy orbitals are filled first. The increasing energy order of orbitals is:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p....

s, p ,d orbitals can accommodate a maximum of 2,6 and 8 electrons respectively.

Based on the above ordering, the most reasonable ground state configuration would be:

1s2 2s2 2p6 3s2 3p6 4s2 4d8

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What is the mass of an atom with 15 neutrons and 13 electrons ?

slava [35]

The mass would be 28. The mass of an atom equals the number of neutrons and protons added together. In this case, they do not say the protons. But we must use our inside knowledge to know that the number of protons equals the number of electrons. Thus, your number of protons would be 13

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2 years ago

Instead of using ratios for back titrations we can also use molarities, if our solutions are standardized. A 0.196 g sample of a

kvv77 [185]

Answer:

The mass percent of Al(OH)₃ is 15.3%

Explanation:

The reaction is:

Al(OH)₃ + 3HCl = AlCl₃ + 3H₂O

The excess acid is neutralized with a solution of sodium hidroxide, in the reaction:

NaOH + HCl = NaCl + H₂O

The total moles of HCl is:

$n_{HCl,total} =M_{HCl} *V_{HCl} =0.111*0.025=2.78x10^{-3} moles$

From the second titration, the moles of excess of HCl is:

$n_{HCl,excess} =n_{NaOH} =M_{NaOH} *V_{NaOH} =0.132*0.01105=1.46x10^{-3} moles$

The difference between the total and excess of HCl, it can be know the moles that reacts with the aluminum hydroxide, is:

$n_{HCl,reacts} =n_{HCl,total}-n_{HCl,excess} =2.78x10^{-3} moles-1.46x10^{-3} moles=1.32x10^{-3} moles$

The ratio between HCl and Al(OH)₃ is 3:1. The MW for aluminum hydroxide is 78 g/mol, thus:

$m_{Al(OH)3} =1.32x10^{-3} molesHCl*\frac{1molAl(OH)3}{3molesHCl} *\frac{78gAl(OH)3}{1molAl(OH)3} =0.03g$

The percentage of Al(OH)₃ is:

$Percentage-Al(OH)3=\frac{m_{Al(OH)3} }{m_{antiacid} } *100=\frac{0.03}{0.196} =15.3$ %

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3 years ago

Maple syrup, which comes from the sap of maple trees, is a mixture of water and natural sugars. It's a clear, brown liquid. It's

Margaret [11]

Correct Answer: Option C i.e <span>Solution

Reason:
Solutions are characterized by particles of size less than 1nm. Since the particle size in solutions are very small, they cannot be separated by centrifugation. On other hand, colloids have particle size ranging from 1nm to 100 nm, while suspensions have particle size > 100 nm. Hence, they can be separated by centrifugation. </span>

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3 years ago

Read 2 more answers

Which of the following characteristics is NOT associated with El Niño?

Evgesh-ka [11]

Answer:

I think it's Cooler waters rising to the surface of the ocean.

Explanation:

I've heard of all the others happening. :)

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2 years ago

Read 2 more answers

How many moles of calcium chloride are theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4

Georgia [21]

Answer : The number of moles of calcium chloride theoretically produced are, 1.3 moles.

Explanation : Given,

Moles of HCl = 2.6 moles

Moles of $Ca(OH)_2$ = 1.4 moles

Now we have to calculate the limiting and excess reagent.

The given balanced chemical reaction is:

$2HCl+Ca(OH)_2\rightarrow 2H_2O+CaCl_2$

From the balanced reaction we conclude that

As, 2 mole of $HCl$ react with 1 mole of $Ca(OH)_2$

So, 2.6 moles of $HCl$ react with $\frac{2.6}{2}=1.3$ moles of $Ca(OH)_2$

From this we conclude that, $Ca(OH)_2$ is an excess reagent because the given moles are greater than the required moles and $HCl$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $CaCl_2$

From the reaction, we conclude that

As, 2 mole of $HCl$ react to give 1 mole of $CaCl_2$

So, 2.6 moles of $HCl$ react to give $\frac{2.6}{2}=1.3$ moles of $CaCl_2$

Therefore, the number of moles of calcium chloride theoretically produced are, 1.3 moles.

7 0

3 years ago