Answer:
an increase in 1-butene was observed when t-butoxide was used
Explanation:
When a base reacts with an alkyl halide, an elimination product is formed. This reaction is an E2 reaction.
Here we are to compare the reaction of two different bases with one substrate; 2-bromobutane. Both reactions occur by the E2 mechanism but follow different transition states due to the size of the base.
The Saytzeff product, 2-butene, is obtained when the methoxide is used while the non Saytzeff product, 1-butene, is obtained when t-butoxide is used.
The Saytzeff rule is reliable in predicting the major products of simple elimination reactions of alkyl halides given the fact that a small/strong bases is used for the elimination reaction. Therefore hydroxide, methoxide and ethoxide bases give similar results for the same alkyl halide substrate. Bulky bases such as tert-butoxide tend to yield a higher percentage of the non Saytzeff product and this is usually attributed to steric hindrance.
Your answer is b because it is
The concentration of OH⁻ is first converted to pOH bu using followinf formula,
pOH = -log [OH⁻]
Putting value,
pOH = -log (0.006)
pOH = 2.221
As we know,
pH + pOH = 14
Solving for pH,
pH = 14 - pOH
Putting value of pOH,
pH = 14 - 2.221
pH = 11.779
Result:
Option-1 is the correct answer.
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I couldn't find the answer to your question.
Answer:
- The percentage of unit cell volume that is occupied by atoms in a face- centered cubic lattice is 74.05%
- The percentage of unit cell volume that is occupied by atoms in a body-centered cubic lattice is 68.03%
- The percentage of unit cell volume that is occupied by atoms in a diamond lattice is 34.01%
Explanation:
The percentage of unit cell volume = Volume of atoms/Volume of unit cell
Volume of sphere = 
a) Percentage of unit cell volume occupied by atoms in face- centered cubic lattice:
let the side of each cube = a
Volume of unit cell = Volume of cube = a³
Radius of atoms = 
Volume of each atom =
= 
Number of atoms/unit cell = 4
Total volume of the atoms = 
The percentage of unit cell volume =
= 0.7405
= 0.7405 X 100% = 74.05%
b) Percentage of unit cell volume occupied by atoms in a body-centered cubic lattice
Radius of atoms = 
Volume of each atom =
=
Number of atoms/unit cell = 2
Total volume of the atoms = 
The percentage of unit cell volume =
= 0.6803
= 0.6803 X 100% = 68.03%
c) Percentage of unit cell volume occupied by atoms in a diamond lattice
Radius of atoms = 
Volume of each atom =
= 
Number of atoms/unit cell = 8
Total volume of the atoms = 
The percentage of unit cell volume =
= 0.3401
= 0.3401 X 100% = 34.01%