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2 years ago

what is the ratio of the rate of effusion of helium (atomic mass 4.00 amu) to that of oxygen gas (molecular mass 32.0 amu)?

Chemistry

1 answer:

nignag [31]2 years ago

8 0

Answer:

3 : 1

Explanation:

Let the rate of He be R1

Molar Mass of He (M1) = 4g/mol

Let the rate of O2 be R2

Molar Mass of O2 (M2) = 32g/mol

Recall:

R1/R2 = √(M2/M1)

R1/R2 = √(32/4)

R1/R2 = √8

R1/R2 = 3

The ratio of rate of effusion of Helium to oxygen is 3 : 1

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Joe is concerned about the carbon dioxide emissions from his daily commute and the impact that it is having on global warming In

Vesna [10]

Amount of CO₂ emission per day is 11,356.23 g.

Explanation:

Joe travelling distance per day = 60 miles

Carbon dioxide emission per day = 20 mpg

Now we have to find the amount of carbon dioxide emitted per day by dividing the distance by the emission per day given in gallons.

Amount of Carbon dioxide emission = $$\frac{distance}{emission amount}$

Amount of CO₂ emission in gallons = $$\frac{ 60 miles}{20 mpg}$

= 3 gallons

Now we have to convert the gallons to grams as,

1 gallon = 3,785.41 g

3 gallons = 3 × 3785.41 g = 11,356.23 g

So the emission of CO₂ per day is 11,356.23 g.

6 0

2 years ago

CaO + HCI → CaCl2 + H20

andrew-mc [135]

Explanation:

To balance this chemical equation-

see

Balanced form:-

CaO + 2 HCl ==. CaCl2 + H2O

7 0

2 years ago

What is the full meaning of DR.HERC.

n200080 [17]

Answer:

It is

D- DEFINE the problem

R-RESEARCH on the problem

H- Carry out a HYPOTHESIS

E- carry out an EXPERIMENT.

R-Analyse the RESULT

C-summarise the CONCLUSION.

Explanation:

Hope it helps.

5 0

2 years ago

The specific heat of ethanol is 2.44 J/g ֯C. How many kJ of energy are required to heat 50.0 grams of ethanol from -20 ֯C to 68

Aliun [14]

Answer:

Heat energy required (Q) = 10.736 KJ

Explanation:

Given:

Specific heat of ethanol (C) = 2.44 J/g °C

Mass of ethanol (M) = 50 gram

Initial temperature (T1) = -20°C

Final temperature (T1) = 68°C

Find:

Heat energy required (Q) = ?

Computation:

Change in temperature (ΔT) = 68°C - (-20°C)

Change in temperature (ΔT) = 88°C

Heat energy required (Q) = mC(ΔT)

Heat energy required (Q) = (50)(2.44)(88)

Heat energy required (Q) = 10,736 J

Heat energy required (Q) = 10.736 KJ

5 0

3 years ago

If the molar mass of the compound in problem 3 is 73.8 grams/mole? what is the molecular formula ?

umka21 [38]

The molecular formula would be Li2CO3

7 0

2 years ago