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Verizon [17]
3 years ago
7

The following ions contain the same number of electrons. Rank them in order of decreasing ionic radii. Rank from largest to smal

lest radius. To rank items as equivalent, overlap them. se3+ cl-
Chemistry
1 answer:
solong [7]3 years ago
8 0

Cl- < Se3+ is the decreasing order of ionic radii of the two ions.

Explanation:

Atomic number of Se= 34 Se3+ will have 31 electrons (+ sign indicates loss of electron)

Atomic number of chlorine is 17, Cl- will have 18 electrons (- sign shows gain of electrons)

Number of electrons in their valence shell:

Se3+ = 2,8,18,3

Cl- = 2,8,8

The Se3+ atoms have K.L.M.N shells while Cl- K,L,M shells

The size of the ions is based on the effective nuclear charge on the ion. The loss in electron causes small cation and gain in electron causes increase in anion size.

The number of occupied shells more the number more is the ionic radii.

Se3+ will have large ionic radii as Se+ has four filled shells.

Cl- < Se3+ (decreasing order of ionic radii)

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AlladinOne [14]

Answer:

A

Explanation:

5 0
2 years ago
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Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, how many
prisoha [69]

337.92 moles of Ozone will be produced

1 Oxygen atom is 8 g

1 mole of ozone, O3 = 8 * 3 = 24 g

7.92 * 1024 = 8110.08 g

1 mole = 24 g

? moles = 8110.08 g

? = 337.92 moles


Read more on moles here:

brainly.com/question/15356425

Hope it helps

7 0
2 years ago
Explain how changing the concentration The enthalpy change for the reaction, 3CO (g) 2Fe2O3 (s) Imported Asset Fe(s) 3CO2 (g), c
ycow [4]

<u>Answer:</u> For the given equation, only iron has the value of \Delta H_f equal to 0 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H^o

The equation used to calculate enthalpy change is of a reaction is:

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]

For the given chemical reaction:

3CO(g)+2Fe_2O_3(s)\rightarrow Fe(s)+3CO_2(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(Fe(s))})+(3\times \Delta H^o_f_{(CO_2(g))})]-[(3\times \Delta H^o_f_{(CO(g))})+(2\times \Delta H^o_f_{(Fe_2O_3(s))})]

The enthalpy of formation for the substances present in their elemental state is taken as 0.

Here, iron is present in its elemental state which is solid.

Hence, for the given equation, only iron has the value of \Delta H_f equal to 0 kJ.

7 0
3 years ago
-2(bx-5)=16 slove for b<br>​
Papessa [141]

Explanation:

SADMEP

-2(bx-5) = 16 distribute

-2bx +10 = 16 subtracte

-10 -10

-2bx = 6

divide by -2x (on both sides)

b = -3x

6 0
2 years ago
Read 2 more answers
A sample of a gas has a volume of 852 mL at 298 K. If the gas is cooled to 200K, what would the new volume be?
Colt1911 [192]

Answer:

571.81 mL

Explanation:

Assuming constant pressure, we can solve this problem by using <em>Charles' law</em>, which states that at constant pressure:

  • V₁T₂=V₂T₁

Where in this case:

  • V₁ = 852 mL
  • T₂ = 200 K
  • V₂ = ?
  • T₁ = 298 K

We <u>input the data</u>:

  • 852 mL * 200 K = V₂ * 298 K

And <u>solve for V₂</u>:

  • V₂ = 571.81 mL

The new volume would be 571.81 mL.

4 0
2 years ago
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