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Verizon [17]
3 years ago
7

The following ions contain the same number of electrons. Rank them in order of decreasing ionic radii. Rank from largest to smal

lest radius. To rank items as equivalent, overlap them. se3+ cl-
Chemistry
1 answer:
solong [7]3 years ago
8 0

Cl- < Se3+ is the decreasing order of ionic radii of the two ions.

Explanation:

Atomic number of Se= 34 Se3+ will have 31 electrons (+ sign indicates loss of electron)

Atomic number of chlorine is 17, Cl- will have 18 electrons (- sign shows gain of electrons)

Number of electrons in their valence shell:

Se3+ = 2,8,18,3

Cl- = 2,8,8

The Se3+ atoms have K.L.M.N shells while Cl- K,L,M shells

The size of the ions is based on the effective nuclear charge on the ion. The loss in electron causes small cation and gain in electron causes increase in anion size.

The number of occupied shells more the number more is the ionic radii.

Se3+ will have large ionic radii as Se+ has four filled shells.

Cl- < Se3+ (decreasing order of ionic radii)

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(You do) If you have 47.2 mol of Na available, along with an excess of Cl₂, how many grams of NaCl can you produce?
IrinaVladis [17]

Answer:

2,760 grams NaCl

Explanation:

To find grams of NaCl, you need to (1) convert moles of Na to moles of NaCl (via mole-to-mole ratio from reaction) and (2) convert moles of NaCl to grams (via molar mass from periodic table). The final answer should have 3 significant figures based on the given measurement.

2 Na + Cl₂ --> 2 NaCl

Molar Mass (NaCl) = 22.99 g/mol + 35.45 g/mol

Molar Mass (NaCl) = 58.44 g/mol

47.2 moles Na           2 moles NaCl              58.44 grams

----------------------  x  ---------------------------  x  -------------------------  =
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= 2,758.368 grams NaCl

= 2,760 grams NaCl

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