Negative association. There is an outlier, the data moves positively, and there is a large cluster in the graph data.
5.4 dawg
if i did it the way i think it asks
hope it helps!!
Answer:
The coordinate of pre-image is, B(3 , -9).
Step-by-step explanation:
Given an image point has coordinate B'(7, -4).
We have to find the coordinates of its pre-image:
The rule of translation on pre-image (x, y) is given by;

then;
(7, -4) = (x+4, y+5)
on comparison we have;
x+4 = 7 and y + 5 = -4
First solve for x;

Subtract 4 from both sides we have;
x + 4 -4 =7-4
Simplify:
x = 3
To solve for y;
y+5 = -4
Subtract 5 from both sides we get;
y = -9
Therefore, the coordinate of pre-image is, B(3, -9)
Answer/Step-by-step explanation:
4x - 7 = -2x + 12 (Given)
Add 2x to both sides
4x - 7 + 2x = -2x + 12 + 2x (Addition property of equality)
6x - 7 = 12 (Simplication)
Add 7 to both sides
6x - 7 + 7 = 12 + 7 (Addition property of equality)
6x = 19 (Simplification)
Divide both sides by 6
(Division property of equality)

The graph is raised by the value of that constant (if it is negative, it is lowered by that much)