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anygoal [31]
3 years ago
5

You want to limit the amount of television you watch to an average of at most two hours per week do an eight week. How many hour

s acts of television must you watch in the eighth week to meet your goal.
PLEASE SHOW YOUR WORK
Mathematics
1 answer:
igomit [66]3 years ago
7 0

Answer:

16 hours acts of television we must watch in eighth weeks to meet your goal.

Step-by-step explanation:

This problem requires us to determine the total hours we spend on watching television in eight week if we spend two hours watching television each week. This problem can easily be solved by multiplying 2 hours with number of week that is 8 week.

= 8 * 2 = 16

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Lisa earns $2.50 a week and lives in a state that taxes and come at 5%. How much does Lisa pay in state tax each week?
vaieri [72.5K]

Answer:

Step-by-step explanation:

Weekly tax that Lisa pay is 5% of her weekly earning at $2.50

= 5/100× $2.50=$0.125

7 0
3 years ago
A cable company offers two movie plans. Plan A costs $120 per month plus $5 per movie. Plan B costs $150 per month for unlimited
horsena [70]

Answer: he could watch a maximum of 6 movies with plan A and still pay the same but the better deal is plan B. I hope that this helps! :)

Step-by-step explanation:

6 0
2 years ago
Seth traveled 1 mile in 57.1 seconds. About hos fast does Seth travel in miles per hour?
mars1129 [50]

Seth traveled 1mi/57.1s

you need to convert mi/s to mi/h

we need to found how many seconds are in an hour (3,600)

so 3,600/57.1=63.047

63.047mi/h

63mi/h (rounding)

8 0
3 years ago
An analysis of sales records for the last 120 weeks gives the following results. Assuming that these past data are a reliable gu
Mila [183]

Answer:

(a) 0.5333

(b) 0.6583

(c) 0.5583

(d) 0.7083

(e) 0.6167

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = a competitor will advertise

<em>NA </em>= a competitor will not advertise

<em>L </em>= Low sales will be achieved

<em>M </em>= Medium sales will be achieved

<em>H </em>= High sales will be achieved

The data provided is of the form:

          Low (L)    Medium (M)    High (H)    Total    

A            32                   14                 18               64

NA          21                   12                 23              56

Total      53                  26                 41              120

The probability of an event <em>E</em> is:

P(E)=\frac{n(E)}{N}

n (E) = favorable outcomes of event <em>E</em>

N = Total number of outcomes

(a)

Compute the probability that next week the competitor will advertise as follows:

P(A)=\frac{n(A)}{N}=\frac{64}{120}=0.5333

Thus, the probability that next week the competitor will advertise is 0.5333.

(b)

Compute the probability that next week sales will not be high as follows:

P(H^{c})=1-P(H)=1-\frac{n(H)}{N}=1-\frac{41}{120}=\frac{120-41}{120}=0.6583

Thus, the probability that next week sales will not be high is 0.6583.

(c)

The events of achieving a medium or high sales are mutually exclusive.

Since the sales achieved will either be medium or high. They cannot be both.

So, P (M ∩ H) = 0.

Compute the probability that next week there will be medium or high sales will be achieved as follows:

P(M\cup H)=P(M)+P(H)=\frac{26}{120}+\frac{41}{120}=\frac{26+41}{120}=0.5583

Thus, the probability that next week there will be medium or high sales will be achieved is 0.5583.

(d)

Compute the probability that next week either the competitor will advertise, or only low sales will be achieved as follows:

P(A\cup L)=P(A)+P(L)-P(A\cap L)=\frac{64}{120}+\frac{53}{120}-\frac{32}{120}=\frac{85}{120}=0.7083

Thus, the  the probability that next week either the competitor will advertise, or only low sales will be achieved is 0.7083.

(e)

Compute the probability that next week either the competitor will not advertise, or high sales will be achieved as follows:

P(NA\cup H)=P(NA)+P(H)-P(NA\cap H)=\frac{56}{120}+\frac{41}{120}-\frac{23}{120}=\frac{74}{120}=0.6167

Thus, the  the probability that next week either the competitor will not advertise, or high sales will be achieved is 0.6167.

8 0
3 years ago
In art class,Kerion is coloring a pattern where half of the squares on her paper are being colored blue. Of the blue squares,1/3
stiv31 [10]
To get the fraction of blue squares with stripes we shall proceed as follows;
fraction of blue squares=1/2
1/3 of the blue squares have stripes, therefore we shall have:
fraction of blue square with stripes
=1/3 of 1/2
=1/3×1/2
=1/6
Hence we conclude that the fraction of blue squares with stripes was 1/6 of the total colored squares.
7 0
3 years ago
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