If the density of a certain alcohol is 0.785 g/mL, what volume of the alcohol would have a mass of 75.0 g
2 answers:
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The concentration of the HBr would be 0.09 M
<h3>What are stoichiometric problems?</h3>First, let us look at the equation of the reaction:
The mole ratio of HBr to NaOH is 1:1.
Mole of 15 mL, 0.30 M NaOH = 0.30 x 15/1000 = 0.0045 moles
Equivalent mole of HBr - 0.0045 moles
Molarity of HBr = mole/volume = 0.0045/50/1000 = 0.09 M
More on stoichiometric problems can be found here: brainly.com/question/15047541
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Answer:
The correct option is: e) n=4, l=3, = - 2 ,
= - 1/2
Explanation:
The four quantum numbers that describe the electrons in an atom are: The principal: n, azimuthal: l, magnetic: m, and spin: s.
For a given electron, the values of the quantum numbers should be in the <u>given range</u>- principal quantum number: n ≥ 1;
azimuthal quantum number: 0 ≤ l ≤ n − 1;
magnetic quantum number: −l ≤ ≤ +l;
spin quantum number: −s ≤ ≤ +s
Now, for n= 4,
The value of l: 0 to n − 1 = 0 to 3 = 0, 1, 2, 3
The value of for l= 3 : -3 to +3 = -3, -2, -1, 0, +1, +2, +3
The value of : -1/2, +1/2
<u>Therefore, the given set of quantum numbers</u>: n=4, l=3, = - 2 ,
= - 1/2; <u>are possible and permissible for an electron in an atom.</u>