When trying to determine whether or not an atom gives up electrons easily, do chemists look at electronegativity or ionization p
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Given information : Volume of HCl = 32.40 mL
Volume of HCl = 0.0324 L
Concentration of HCl = 0.185 M or 0.185 mol/L (M = mol/L)
Volume of Ca(OH)2 = 27.0 mL
Volume of Ca(OH)2 = 0.027 L
We need to find the concentration of Ca(OH)2.
To find the concentration of Ca(OH)2 we need moles and volume of Ca(OH)2.
Moles of Ca(OH)2 can be calculated using stoichiometry and volume of Ca(OH)2 is already given to us.
Step 1 : Find the moles of HCl using its given volume and concentration.
Moles of HCl = 0.005994 mol HCl
Step 2 : We need to find moles of Ca(OH)2 using mol of HCl with the help of mole ratio.
Mole ratio are the coefficient present in front of the compound in a balanced equation.
Mole ratio of Ca(OH)2 : HCl = 1:2 ( 1 coefficient of Ca(OH)2 and 2 coefficient of HCl)
Moles of Ca(OH)2 = 0.002997 mol Ca(OH)2
Step 3 : Find the concentration of Ca(OH)2 using its moles and volume.
Moles of Ca(OH)2 = 0.002997 mol and volume of Ca(OH)2 = 0.027 L
Concentration of Ca(OH)2 = 0.111 mol/L or 0.111 M
Answer:
Explanation:
We will need an equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 315.46 76.12
Ba(OH)₂·8H₂O + 2NH₄SCN ⟶ Ba(SCN)₂ + 2NH₃ + 10H₂O
m/g: 6.5
1. Moles of Ba(OH)₂·8H₂O
2. Moles of NH₄SCN
The molar ratio is 2 mol NH₄SCN:1 mol Ba(OH)₂·8H₂O
3. Mass of NH₄SCN