Answer:
Explanation:
To find out the angular velocity of merry-go-round after person jumps on it , we shall apply law of conservation of ANGULAR momentum
I₁ ω₁ + I₂ ω₂ = ( I₁ + I₂ ) ω
I₁ is moment of inertia of disk , I₂ moment of inertia of running person , I is the moment of inertia of disk -man system , ω₁ and ω₂ are angular velocity of disc and man .
I₁ = 1/2 mr²
= .5 x 175 x 2.13²
= 396.97 kgm²
I₂ = m r²
= 55.4 x 2.13²
= 251.34 mgm²
ω₁ = .651 rev /s
= .651 x 2π rad /s
ω₂ = tangential velocity of man / radius of disc
= 3.51 / 2.13
= 1.65 rad/s
I₁ ω₁ + I₂ ω₂ = ( I₁ + I₂ ) ω
396.97 x .651 x 2π + 251.34 x 1.65 = ( 396.97 + 251.34 ) ω
ω = 3.14 rad /s
kinetic energy = 1/2 I ω²
= 3196 J
Answer:
Explanation:
Givens
d = 115 km
r = 80 km/hr
t = ?
Equation
d = r*T
Solution
115 = 80 * t Divide by 80
115/80 = t
t = 1.4375 hours.
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From the planks equation
E=hv
V= c/ wave length
V= 3×10^8/30×10^-9
=1×10^16
E= hv
6.63×10^-34×1×10^16
= 6.63×10^-18
<h3>No:1</h3>
The object is moving with constant or uniform acceleration and in average speed
<h3>No:-2</h3>
The object is de accelerating
<h3>No:-3</h3>
The object deaccelerated and came to rest so fast.
<h3>No:-4</h3>
The object moves slowly first then accelerated.
<h3>No:-5</h3>
The object accelerated at first so fast then move with constant acceleration then again accelerated .