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mezya [45]
2 years ago
11

A stubborn, 120 kg mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope around t

he mule and pulls with his maximum force of 800 N. The coefficients of friction between the mule and the ground are μs=0.8 and μk=0.5. Is the farmer able to move the mule?
Physics
1 answer:
Helen [10]2 years ago
8 0

Answer:

No

Explanation:

In order for the farmer to be able to put the mule in motion, the force he applies must be larger than the maximum value of the force of static friction exerted by the ground on the mule.

The maximum value of the force of static friction on the mule is given by:

F_f=\mu_s mg

where:

\mu_s=0.8 is the coefficient of static friction

m = 120 kg is the mass of the mule

g=9.8 m/s^2 is the acceleration due to gravity

Substituting, we find:

F_f=(0.8)(120)(9.8)=941 N

Here in this problem, the force applied by the farmer through the rope is

F = 800 N

We see that this force is smaller than the value of the maximum force of friction: therefore, the farmer will not be able to move the mule.

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Three 7 0hm resistors are connected in series across a 10 V battery. What is the equivalent resistance of the circuit?
Tomtit [17]

Given

Three 7 ohm resistor are in series.

The battery is V=10V

To find

The equivalent resistance

Explanation

When the resistance are in series then the resistance are added to find its equivalent.

Thus the equivalent resistance is:

R=7+7+7=21\Omega

Conclusion

The equivalent resistance is 21 ohm

4 0
10 months ago
A 20.0 cm tall object is placed 50.0 cm in front of a convex mirror with a radius of curvature of 34.0 cm. Where will the image
Neko [114]

Answer:

1.Theimage will be located at -0.13m or -13 cm

2.The height of the image will be 0.052m or 5.2cm

Explanation:

Given that;

Height of object, h=20 cm = 0.2m

Object distance in front of convex mirror, o,= 50 cm =0.5m

Radius of curvature, r, =34 cm =0.34m

Let;

Image distance, i,=?

Image height, h'=?

You know that focal length,f, is half the radius of curvature,hence

f=r/2 = 0.34/2 = 0.17m ( this length is inside the mirror, in a virtual side, thus its is negative)

f= -0.17m

Apply the relationship that involves the focal length;

=\frac{1}{o} +\frac{1}{i} =\frac{1}{f}

=\frac{1}{0.5} +\frac{1}{i} =-\frac{1}{0.17}

Re-arrange to get i

\frac{1}{i} =-2-5.88\\\\\\\frac{1}{i} =-7.88\\\\i=-0.13m

This is a virtual image formed at a negative distance produced through extension of drawing rays behind the mirror if you use rays to locate the image behind the mirror

Apply the magnification formula

magnification, m=height of image÷height of object

m=\frac{h'}{h} =-\frac{i}{o}

substitute the values to get the height of image h'

\frac{h'}{0.20} =-\frac{-0.13}{0.5} \\\\\\h'=\frac{0.13*0.20}{0.5} \\\\\\h'=\frac{0.025}{0.5} =0.052m\\\\\\h'=5.2cm

5 0
3 years ago
Select the correct term to complete each sentence. If you the wavelength, the electromagnetic radiation energy will double. The
Andrews [41]

Answer:

A) If you halve the wavelength, the electromagnetic radiation energy will double.

B) The energy of the electromagnetic radiation will halve if you halve the wavenumber.

C) When the frequency of the light is doubled, its energy will double.

Explanation:

The function for the light frequency is given as

The energy supplied to each electron is doubled by halving the wavelength, nearly doubling its kinetic energy by two after it is free from the metal. It is important to remember that for a given period of time, the number of electrons ejected will remain constant.

Cheers

5 0
2 years ago
Which simple experiment could be conducted to show an example of how lightning is created? A) Rub a balloon so it picks up extra
alexandr1967 [171]

I think the answer is d

7 0
3 years ago
An object has a weight of 9 n when it is in air and 7.2 n when it is submerged into water. what is the specific gravity of the o
White raven [17]

The specific gravity of the object’s material is 5.09.

<h3>To calculate the specific gravity of the object:</h3>

Weight difference = 9 - 7.2 = 1.8 N = Buoyant force of water

Buoyant Force in water(Fb) = density of water x g x volume of the   body(Vb)

1.8 = 1000 x 9.81 x Vb

Vb = 1.8/9810 cubic meter

Now, in the air;

Weight of body = mg = 9 N

Mass of body,m = 9/9.81 Kg

So,

Density of body = m/ Vb

= 9/9.81 ÷ 1.8/9810

= 5094.44 kg per cubic meter

The specific gravity of body = density of body ÷ density of water

= 5094.44 ÷ 1000

= 5.09

Therefore, Specific gravity of body = 5.09

Learn more about Specific gravity here:

brainly.com/question/13258933

#SPJ4

6 0
1 year ago
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