A stubborn, 120 kg mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope around t
1 answer:
Answer:
No
Explanation:
In order for the farmer to be able to put the mule in motion, the force he applies must be larger than the maximum value of the force of static friction exerted by the ground on the mule.
The maximum value of the force of static friction on the mule is given by:
where:
is the coefficient of static friction
m = 120 kg is the mass of the mule
is the acceleration due to gravity
Substituting, we find:
Here in this problem, the force applied by the farmer through the rope is
F = 800 N
We see that this force is smaller than the value of the maximum force of friction: therefore, the farmer will not be able to move the mule.
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The average velocity for the time period beginning when t=1 and lasting
(i) 0.01 seconds = 63.84 ft/s
(ii) 0.001 seconds = 63.984 ft/s
Given that a ball is thrown with an initial velocity = 80 ft/s
Let 'y' be the height in feet after 't' seconds.
Given, gives the height in 't' seconds.
Average velocity = Rate of change of distance
= Change in distance/Change in time.
The initial time can be taken as 0 s.
When t =1 s, y = 80 - 16 = 64 ft
(1) t = 0.01 s
y = 80 x 0.01 - 16 x 0.01 x 0.01 = 0.7984 ft
Average velocity = (64 - 0.7984) / (1 -0.01) = 63.84 ft/s
(2) t = 0.001 s
y = 80 x 0.001 - 16 x 0.001 x 0.001 = 0.079984 ft
Average velocity = (64 - 0.079984) / (1 -0.001) = 63.984 ft/s
The question is incomplete. Find out the complete question below:
If a ball is thrown straight up into the air with an initial velocity of 80 ft/s, it height in feet after t second is given by .Find the average velocity for the time period beginning when t=1 and lasting
(i) 0.01 seconds
(ii) 0.001 seconds
Learn more about average velocity at brainly.com/question/6504879
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The mass of the ion is 5.96 X 10⁻²⁵ kg
<u>Explanation:</u>
The electrical energy given to the ion Vq will be changed into kinetic energy
As the ion moves with velocity v in a magnetic field B then the magnetic Lorentz force Bqv will be balanced by centrifugal force .
So,
and
Right from these eliminating v, we can derive
On substituting the value, we get:
m = 5.96 X 10⁻²⁵ kg.