The correct options are B and C
Let us assume the amplitude of the two sinusoidal waves be A1 and A2
As it is mentioned that the waves are identical, therefore A1=A2= a
The resultant wave of any two waves is given by the formula:
Resultant wave= ![\sqrt{A1^2+A2^2+2A1A2cos\alpha }](https://tex.z-dn.net/?f=%5Csqrt%7BA1%5E2%2BA2%5E2%2B2A1A2cos%5Calpha%20%7D)
where A1 and A2 are amplitudes of waves 1 and 2 and
is the angle between the waves
Now as per the formula, it is the the factor 2cos
that will decide that amplitude is greater than original or not
Hence we know that maximum value of cos
is when
is 0 degrees
Now it is known that value of cos
varies from 1 to 0 for o degrees to π/2
and the value varies from 0 to -1 for angles π/2 to π
Case 1: when
=0 degree
Resultant wave R = ![\sqrt{A1^2+A2^2+2cos0A1A2}= \sqrt{2A^2+2A^2}=\sqrt{4A^2} =2A](https://tex.z-dn.net/?f=%5Csqrt%7BA1%5E2%2BA2%5E2%2B2cos0A1A2%7D%3D%20%5Csqrt%7B2A%5E2%2B2A%5E2%7D%3D%5Csqrt%7B4A%5E2%7D%20%20%20%3D2A)
Case 2: When
is less than 90
let us consider ![\alpha = 45 degree](https://tex.z-dn.net/?f=%5Calpha%20%3D%2045%20degree)
Resultant wave R =
![\sqrt{A1^2+A2^2+2cos45A1A2}= \sqrt{2A^2+2A^2/2}=\sqrt{3A^2} =\sqrt{3} A](https://tex.z-dn.net/?f=%5Csqrt%7BA1%5E2%2BA2%5E2%2B2cos45A1A2%7D%3D%20%5Csqrt%7B2A%5E2%2B2A%5E2%2F2%7D%3D%5Csqrt%7B3A%5E2%7D%20%20%20%3D%5Csqrt%7B3%7D%20A)
case 3:
When
is less than 120
![\sqrt{A1^2+A2^2+2cos120A1A2}= \sqrt{2A^2-2A^2/2}=A](https://tex.z-dn.net/?f=%5Csqrt%7BA1%5E2%2BA2%5E2%2B2cos120A1A2%7D%3D%20%5Csqrt%7B2A%5E2-2A%5E2%2F2%7D%3DA)
case 4: when
is less than 180 degrees
the value will be 0
Hence only option b and d are correct
For further reference:
brainly.com/question/14286615?referrer=searchResults
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Answer: The focus is the place inside Earth's crust where an earthquake originates. The point on the Earth's surface directly above the focus is the epicenter. The epicenter is the point on the surface above the focus, the place on the surface that would receive the most intense vibrations.
Explanation: Hope it helps <3
Refractive index of a medium = speed of light in vacuum
-------------------------------------
speed of light in that medium
Answer:
distance traveled is 15 mi
displacement is 5 mi
Explanation:
Distance takes time into account and adds up all the tiny displacements during the entire period of the trip.
Displacement ignores time and looks only at the change in position from the starting point to the ending point.