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3 years ago

Multiply. −2/21×27/40 Enter your answer as a fraction, in simplified form, in the box.

Mathematics

1 answer:

Taya2010 [7]3 years ago

3 0

That would be -12852/125 I believe

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How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove

BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

$\dfrac{9}{n^2+1} =\dfrac{n+3}{4}$

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

$\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\$

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y

with 0 and solve for x. The graph of the equation is attached.

n ≈ 2.38450287

Hence, The equation has one extraneous solution which is n ≈ 2.38450287

For more information refer to the link.

brainly.com/question/15070282

5 0

3 years ago

Matt gave 5 apples to his son and sold 8 times as many apples. If Matt had 1/2 of the apples left, how many did he have in the b

Gala2k [10]

Answer:

Step-by-step explanation:

8*5 = 40

40 + 5 = 45

1/2 x = 45

x = 90

4 0

3 years ago

Read 2 more answers

Solve the compound inequality. 3x>3 or 5x<2x-3

tekilochka [14]

$5x\ \textless \ 2x-3$

$
5x-2x\ \textless \ -3
 
$ $Subtract \ 2x \ from \ both \ sides$

$3x\ \textless \ -3

 
$

$x\ \textless \ - \dfrac{3}{3}$ $Divide \ both \ sides \ by \ 3$

$x$

7 0

4 years ago

In tossing four fair dice, what is the probability of tossing, at most, one 3

11Alexandr11 [23.1K]

Answer-

In tossing four fair dice, the probability of getting at most one 3 is 0.86.

Solution-

The probability of getting at most one 3 is, either getting zero 3 or only one 3.

$P(A) =The \ probability \ of \ getting \ zero \ 3 =(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})=\frac{625}{1296} =0.48$ ( ∵ xxxx )

$P(B) = The \ probability \ of \ getting \ only \ one \ 3 =(4)(\frac{1}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6}) = 0.38$ ( ∵ 3xxx, x3xx, xx3x, xxx3 )

P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86

7 0

3 years ago

Will you check my math its supposed to be a face!

LUCKY_DIMON [66]

It looks like a face to me

6 0

3 years ago

Multiply. ​ −2/21×27/40 ​ Enter your answer as a fraction, in simplified form, in the box.

Multiply. −2/21×27/40 Enter your answer as a fraction, in simplified form, in the box.