Answer:
20.7 cm³
Explanation:
From the question given above, the following data were obtained:
Initial volume (V1) = 20 cm³
Initial temperature (T1) = 5 °C
Initial pressure (P1) = 760 mm Hg
Final temperature (T2) = 30 °C
Final pressure (P2) = 800 mm Hg
Final volume (V2) =?
Next we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
Temperature (K) = Temperature (°C) + 273
Initial temperature (T1) = 5 °C
Initial temperature (T1) = 5 °C + 273 = 278 K.
Final temperature (T2) = 30 °C
Final temperature (T2) = 30 °C + 273 = 303 K.
Finally, we shall determine the new volume of the gas as follow:
Initial volume (V1) = 20 cm³
Initial temperature (T1) = 278 K
Initial pressure (P1) = 760 mm Hg
Final temperature (T2) = 303 K
Final pressure (P2) = 800 mm Hg
Final volume (V2) =?
P1V1/T1 = P2V2/T2
760 × 20 /278 = 800 × V2/303
Cross multiply
278 × 800 × V2 = 760 × 20 × 303
Divide both side by 278 × 800
V2 = (760 × 20 × 303) / (278 × 800)
V2 = 20.7 cm³
Therefore, the new volume of the gas is 20.7 cm³
, so the area enclosed by the loop is
