Answer:
When the volume increases or when the temperature decreases
Explanation:
The ideal gas equation states that:
where
p is the gas pressure
V is the volume
n is the number of moles of gas
R is the gas constant
T is the gas temperature
Assuming that we have a fixed amount of gas, so n is constant, we can rewrite the equation as
which means the following:
- Pressure is inversely proportional to the volume: this means that the pressure decreases when the volume increases
- Pressure is directly proportional to the temperature: this means that the pressure decreases when the temperature decreases
Answer: 8 * 10⁻⁸ cm² .
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Explanation:
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(2 * 10⁴ cm) * (4 * 10⁻¹² cm) =
2 *4 * 10⁴ * 10⁻¹² = 8 * 10⁽⁴⁺⁽⁻¹²⁾⁾ = 8 * 10⁻⁸ cm² .
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Note the follow property of exponents:
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xᵃ * xᵇ = x⁽ᵃ ⁺ ᵇ⁾ ; as such: " 10⁴ * 10⁻¹² = 10⁽⁴⁺⁽⁻¹²⁾⁾ = 10⁻⁸ " .
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Answer:
The answer to the question above is explained below
Explanation:
The reaction quotient, Q, is a measure of the relative amounts of reactants and products during a chemical reaction as it can be used to determine in which direction a reaction will proceed at a given point in time. Equilibrium constant is the numerical value of reaction quotient at the end of the reaction, when equilibrium is reached.
If Q = K then the system is already at equilibrium. If Q < Keq, the reaction will move toward the products to reach equilibrium. If Q > Keq, the reaction will move toward the reactants in order to reach equilibrium. Therefore, by comparing Q and K, we can determine the direction of a reaction.
Where Q= reaction quotient and Keq= equilibrium constant for the reaction.
The larger the equilibrium constant, the further the equilibrium lies toward the products. Reaction quotient is a quantity that changes as a reaction system approaches equilibrium.
We can determine the equilibrium constant based on equilibrium concentrations. K is the constant of a certain reaction when it is in equilibrium. Equilibrium occurs when there is a constant ratio between the concentration of the reactants and the products.
Answer:
The magnitude of the radial acceleration is 0.754 rad/s²
Explanation:
Given;
radius of the flywheel, r = 0.2 m
initial angular velocity of the flywheel, 
angular acceleration of the flywheel, a = 0.900 rad/s².
angular distance, θ = 120⁰
the angular distance in radian = 
Apply the following kinematic equation to determine the final angular velocity;
The magnitude of the radial acceleration is calculated as;
Therefore, the magnitude of the radial acceleration is 0.754 rad/s²
Explanation:
thet amplify DC, because of the voltage ( small current input signal)
