Question

A 440 kg roller coaster car is going 26 m/s when it reaches the lowest point on the track. If the car started from rest at the top of a hill, how much higher was that point on the track than the lowest point? (Use g = 9.80 m/s2, and ignore friction.)
17 m
23 m
34 m
69 m

Answer 1

Answer: The correct answer is 34.5 m.

Explanation:

The equation of motion is as follows;

$v^{2} -u^{2}= 2as$

Here, v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance.

It is given in the problem that a car starts from rest at the top of a hill. A 440 kg roller coaster car is going 26 m/s when it reaches the lowest point on the track.

$v^{2} -u^{2}= 2gs$

Here, g is the acceleration due to gravity.

Put g= 9.80 m/s^2, u=0 and v= 26 m/s.

$(26)^{2} -(0)^{2}= 2(9.8)s$

$s=\frac{676}{19.6}$

$s= 34.5 m$

Therefore, the correct answer is 34.5 m.

Answer 2

34 m I just took the quiz